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Pertanyaan

( 16 x 5 y 3 ) ⋅ ( 2 3 1 ​ x − 3 y − 2 ) = ...

  1. 2 x squared

  2. x squared

  3. 2 x y

  4. 2 x squared y

  5. 2

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R. Hajrianti

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah D.

jawaban yang tepat adalah D.

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Pembahasan

Ingat kembali: Sehingga diperoleh perhitungan: Dengan demikian, nilai dari adalah . Jadi, jawaban yang tepat adalah D.

Ingat kembali:

a to the power of n times a to the power of m equals a to the power of n plus m end exponent

a to the power of negative n end exponent equals 1 over a to the power of n 

a to the power of n equals stack stack a cross times a cross times a cross times... cross times a with underbrace below with a space s a b a n y a k space n below comma space dimana space a not equal to 0  

Sehingga diperoleh perhitungan:

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses 16 x to the power of 5 y cubed close parentheses times open parentheses 1 over 2 cubed x to the power of negative 3 end exponent y to the power of negative 2 end exponent close parentheses end cell equals cell open parentheses open parentheses 2 times 2 times 2 times 2 close parentheses x to the power of 5 y cubed close parentheses times open parentheses 2 to the power of negative 3 end exponent x to the power of negative 3 end exponent y to the power of negative 2 end exponent close parentheses end cell row blank equals cell open parentheses 2 to the power of 4 x to the power of 5 y cubed close parentheses times open parentheses 2 to the power of negative 3 end exponent x to the power of negative 3 end exponent y to the power of negative 2 end exponent close parentheses end cell row blank equals cell 2 to the power of 4 times 2 to the power of negative 3 end exponent times x to the power of 5 times x to the power of negative 3 end exponent times y cubed times y to the power of negative 2 end exponent end cell row blank equals cell 2 to the power of 4 plus open parentheses negative 3 close parentheses end exponent times x to the power of 5 plus open parentheses negative 3 close parentheses end exponent times y to the power of 3 plus open parentheses negative 2 close parentheses end exponent end cell row blank equals cell 2 to the power of 1 times x squared times y to the power of 1 end cell row blank equals cell 2 x squared y end cell end table  

Dengan demikian, nilai dari open parentheses 16 x to the power of 5 y cubed close parentheses times open parentheses 1 over 2 cubed x to the power of negative 3 end exponent y to the power of negative 2 end exponent close parentheses adalah Error converting from MathML to accessible text..

Jadi, jawaban yang tepat adalah D.

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