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t = ( OB ) 2 − ( 2 1 ​ AB ) 2 ​ t = 2 5 2 − ( 2 1 ​ 14 ) 2 ​ t = 2 5 2 − 7 2 ​ t = ... − ... ​ t = ... ​ t = .... L = 2 1 ​ × n × a × t L = 2 1 ​ × 9 × 14 × ... L = ... cm 2

   

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D. Enty

Master Teacher

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begin mathsize 14px style straight t equals square root of open parentheses OB close parentheses squared minus open parentheses begin inline style 1 half end style AB close parentheses squared end root straight t equals square root of 25 squared minus open parentheses begin inline style 1 half end style 14 close parentheses squared end root straight t equals square root of 25 squared minus 7 squared end root straight t equals square root of 625 minus 49 end root straight t equals square root of 576 straight t equals 24 space cm end style

begin mathsize 14px style straight L equals begin inline style 1 half end style cross times straight n cross times straight a cross times straight t straight L equals begin inline style 1 half end style cross times 9 cross times 14 cross times 24 straight L equals 1.512 space cm squared end style    

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Dua buah segitiga siku-siku sama kaki diletakkan dengan posisi seperti gambar. Sudut P dan A merupakan sudut siku-siku. Panjang AB = AC = 24 cm . Panjang PQ = PR . Panjang PQ 4 cm lebih panjang ...

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