Iklan

Iklan

Pertanyaan

t = ( BO ) 2 − ( 2 1 ​ AB ) 2 ​ t = 1 7 2 − ( 2 1 ​ 16 ) 2 ​ t = 1 7 2 − 8 2 ​ t = ... − ... ​ t = ... ​ t = .... L = 2 1 ​ × n × a × t L = 2 1 ​ × 7 × 16 × ... L = ... cm 2

 

Iklan

D. Enty

Master Teacher

Jawaban terverifikasi

Iklan

Pembahasan

Pembahasan
lock

begin mathsize 14px style straight t equals square root of open parentheses BO close parentheses squared minus open parentheses begin inline style 1 half end style AB close parentheses squared end root straight t equals square root of 17 squared minus open parentheses begin inline style 1 half end style 16 close parentheses squared end root straight t equals square root of 17 squared minus 8 squared end root straight t equals square root of 289 minus 64 end root straight t equals square root of 225 straight t equals 15 space cm end style

begin mathsize 14px style straight L equals begin inline style 1 half end style cross times straight n cross times straight a cross times straight t straight L equals begin inline style 1 half end style cross times 7 cross times 16 cross times 15 straight L equals 840 space cm squared end style   

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Shafa Fortuna ramadhani

Jawaban tidak sesuai

Iklan

Iklan

Pertanyaan serupa

Dua buah segitiga siku-siku sama kaki diletakkan dengan posisi seperti gambar. Sudut P dan A merupakan sudut siku-siku. Panjang AB = AC = 24 cm . Panjang PQ = PR . Panjang PQ 4 cm lebih panjang ...

4

3.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia