Pertanyaan

x → 4 lim ​ 4 − x 2 + 7 ​ 9 − x 2 ​

 

E. Nur

Master Teacher

Mahasiswa/Alumni Institut Teknologi Sepuluh Nopember

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Pembahasan

jadi hasilnya adalah .

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 4 of fraction numerator 9 minus x squared over denominator 4 minus square root of x squared plus 7 end root end fraction end cell equals cell fraction numerator 9 minus 4 squared over denominator 4 minus square root of 4 squared plus 7 end root end fraction end cell row blank equals cell fraction numerator negative 7 over denominator 4 minus square root of 23 end fraction end cell row blank equals cell fraction numerator negative 7 over denominator 4 minus square root of 23 end fraction cross times fraction numerator 4 plus square root of 23 over denominator 4 plus square root of 23 end fraction end cell row blank equals cell fraction numerator negative 7 open parentheses 4 plus square root of 23 close parentheses over denominator negative 7 end fraction end cell row blank equals cell 4 plus square root of 23 end cell end table end style

jadi hasilnya adalah begin mathsize 14px style 4 plus square root of 23 end style

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