Pertanyaan

x → 2 lim 4 x + 1 − 3 x 2 − 4 = ....

$x \to 2 lim \frac{x ^{2} - 4}{4 x + 1 - 3} = ....$

D. Entry

Master Teacher

Jawaban terverifikasi

Jawaban

hasil limit fungsi pada soal tersebut adalah .

hasil limit fungsi pada soal tersebut adalah

Pembahasan

Jadi, hasil limit fungsi pada soal tersebut adalah .

$table attributes columnalign right center left columnspacing 0px end attributes row cell limit as straight x rightwards arrow 2 of fraction numerator straight x squared minus 4 over denominator square root of 4 straight x plus 1 end root minus 3 end fraction end cell equals cell limit as straight x rightwards arrow 2 of fraction numerator straight x squared minus 4 over denominator square root of 4 straight x plus 1 end root minus 3 end fraction cross times fraction numerator square root of 4 straight x plus 1 end root plus 3 over denominator square root of 4 straight x plus 1 end root plus 3 end fraction end cell row blank equals cell limit as straight x rightwards arrow 2 of fraction numerator open parentheses straight x squared minus 4 close parentheses open parentheses square root of 4 straight x plus 1 end root plus 3 close parentheses over denominator 4 straight x plus 1 minus 3 squared end fraction end cell row blank equals cell limit as straight x rightwards arrow 2 of fraction numerator open parentheses straight x minus 2 close parentheses left parenthesis straight x plus 2 right parenthesis open parentheses square root of 4 straight x plus 1 end root plus 3 close parentheses over denominator 4 straight x minus 8 end fraction end cell row blank equals cell limit as straight x rightwards arrow 2 of fraction numerator up diagonal strike open parentheses straight x minus 2 close parentheses end strike left parenthesis straight x plus 2 right parenthesis open parentheses square root of 4 straight x plus 1 end root plus 3 close parentheses over denominator 4 up diagonal strike left parenthesis straight x minus 2 right parenthesis end strike end fraction end cell row blank equals cell limit as straight x rightwards arrow 2 of fraction numerator left parenthesis straight x plus 2 right parenthesis open parentheses square root of 4 straight x plus 1 end root plus 3 close parentheses over denominator 4 end fraction end cell row blank equals cell fraction numerator left parenthesis left parenthesis 2 right parenthesis plus 2 right parenthesis open parentheses square root of 4 left parenthesis 2 right parenthesis plus 1 end root plus 3 close parentheses over denominator 4 end fraction end cell row blank equals cell fraction numerator 4 times 6 over denominator 4 end fraction end cell row blank equals 6 end table$

Jadi, hasil limit fungsi pada soal tersebut adalah .