Pertanyaan

N i l ai x p a d a p ers amaan lo g a r i t ma 3 x + 2 lo g 27 = 5 lo g 3 a d a l ah ...

$N i l ai x p a d a p ers amaan lo g a r i t ma^{3 x + 2} lo g 27 =^{5} lo g 3 a d a l ah ...$

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$blank to the power of 3 x plus 2 end exponent log 27 equals to the power of 5 log 3 fraction numerator log 3 cubed over denominator log open parentheses 3 x plus 2 close parentheses end fraction equals fraction numerator log 3 over denominator log 5 end fraction fraction numerator 3. cubed log 3 over denominator blank cubed log open parentheses 3 x plus 2 close parentheses end fraction equals fraction numerator blank cubed log 3 over denominator blank cubed log 5 end fraction fraction numerator 3 over denominator blank cubed log open parentheses 3 x plus 2 close parentheses end fraction equals fraction numerator 1 over denominator blank cubed log 5 end fraction 3 cubed log 5 equals cubed log open parentheses 3 x plus 2 close parentheses up diagonal strike blank cubed log end strike 5 cubed equals up diagonal strike blank cubed log end strike open parentheses 3 x plus 2 close parentheses 5 cubed equals 3 x plus 2 3 x plus 2 equals 125 3 x equals 125 minus 2 3 x equals 123 x equals 123 over 3 x equals 41$