Iklan

Iklan

Pertanyaan

x → ∞ lim ​ ( 2 x − 2 − 4 x 2 − 4 x + 3 ​ )

  

Iklan

A. Salim

Master Teacher

Mahasiswa/Alumni Universitas Pelita Harapan

Jawaban terverifikasi

Jawaban

nilai adalah .

nilai begin mathsize 14px style limit as x rightwards arrow infinity of open parentheses 2 x minus 2 minus square root of 4 x squared minus 4 x plus 3 end root close parentheses end style adalah begin mathsize 14px style negative 1 end style.

Iklan

Pembahasan

Penyelesaikan limit dengan cara berikut. Untuk , diperoleh Jadi, nilai adalah .

Penyelesaikan limit dengan cara berikut.

begin mathsize 14px style limit as x rightwards arrow infinity of square root of a x squared plus b c plus c end root minus square root of p x squared plus q x plus r end root equals open curly brackets table attributes columnalign left end attributes row cell plus infinity space text untuk end text space a greater than p end cell row cell negative infinity text  untuk end text space a less than p end cell row cell fraction numerator b minus q over denominator 2 square root of a end fraction space text untuk end text space a equals p end cell end table close end style 

Untuk begin mathsize 14px style limit as x rightwards arrow infinity of open parentheses 2 x minus 2 minus square root of 4 x squared minus 4 x plus 3 end root close parentheses end style, diperoleh

begin mathsize 12px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow infinity of open parentheses 2 x minus 2 minus square root of 4 x squared minus 4 x plus 3 end root close parentheses end cell equals cell limit as x rightwards arrow infinity of square root of open parentheses 2 x minus 2 close parentheses squared end root minus square root of 4 x squared minus 4 x plus 3 end root end cell row blank equals cell limit as x rightwards arrow infinity of square root of 4 x squared minus 8 x plus 4 end root minus square root of 4 x squared minus 4 x plus 3 end root end cell row blank equals cell fraction numerator negative 8 minus open parentheses negative 4 close parentheses over denominator 2 square root of 4 end fraction end cell row blank equals cell fraction numerator negative 4 over denominator 4 end fraction end cell row blank equals cell negative 1 end cell end table end style 

Jadi, nilai begin mathsize 14px style limit as x rightwards arrow infinity of open parentheses 2 x minus 2 minus square root of 4 x squared minus 4 x plus 3 end root close parentheses end style adalah begin mathsize 14px style negative 1 end style.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

3

Silvi Nuriyah

Jawaban tidak sesuai

Iklan

Iklan

Pertanyaan serupa

Nilai dari L i m x → ∞ ​ ( 7 x − 3 ​ − 7 x + 1 ​ ) =

5

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia