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200 mL larutan dengan pH = 12 dimasukkan ke dalam 300 mL undefined 0,05 M. Jika begin mathsize 14px style K subscript sp space Pb open parentheses O H close parentheses subscript 2 equals 4 cross times 10 to the power of negative sign 16 end exponent end style, apakah terjadi endapan?begin mathsize 14px style space end style 

S. Hidayati

Master Teacher

Mahasiswa/Alumni Universitas Indonesia

Jawaban terverifikasi

Jawaban

campuran tersebut menghasilkan endapan.

Pembahasan

Larutan dengan pH = 12, berarti:

begin mathsize 14px style pOH equals 14 minus sign pH equals 14 minus sign 12 equals 2 end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row 2 equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 10 to the power of negative sign 2 end exponent end cell end table end style 


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets Pb to the power of 2 plus sign close square brackets end cell equals cell fraction numerator V cross times M over denominator V space total end fraction end cell row blank equals cell fraction numerator 300 space mL cross times 0 comma 05 space M over denominator left parenthesis 300 plus 200 right parenthesis space mL end fraction end cell row blank equals cell 0 comma 03 space M end cell end table end style 


undefined 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell Q subscript sp space Pb open parentheses O H close parentheses subscript 2 end cell equals cell open square brackets Pb to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared end cell row blank equals cell left parenthesis 0 comma 03 right parenthesis left parenthesis 10 to the power of negative sign 2 end exponent right parenthesis squared equals 3 cross times 10 to the power of negative sign 6 end exponent end cell end table end style 

Diketahui nilai begin mathsize 14px style K subscript sp space Pb open parentheses O H close parentheses subscript 2 equals 4 cross times 10 to the power of negative sign 16 end exponent end style, Oleh karena nilai begin mathsize 14px style Q subscript sp greater than K subscript sp end style, maka akan terjadi endapan.


Jadi, campuran tersebut menghasilkan endapan.

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