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Pertanyaan

pH larutan jenuh X open parentheses O H close parentheses subscript 2 adalah 9 + log 4. K subscript sp X open parentheses O H close parentheses subscript 2 sebesar ....

  1. 3 comma 2 cross times 10 to the power of negative sign 14 end exponent 

  2. 3 comma 2 cross times 10 to the power of negative sign 15 end exponent 

  3. 6 comma 25 cross times 10 to the power of negative sign 11 end exponent 

  4. 2 comma 56 cross times 10 to the power of negative sign 13 end exponent 

  5. 5 cross times 10 to the power of negative sign 10 end exponent 

F. Aziz

Master Teacher

Jawaban terverifikasi

Pembahasan

Reaksi pelarutan dari X open parentheses O H close parentheses subscript 2 adalah sebagai berikut.
 

X open parentheses O H close parentheses subscript 2 left parenthesis italic s right parenthesis equilibrium X to the power of 2 plus sign left parenthesis italic a italic q right parenthesis plus 2 O H to the power of minus sign left parenthesis italic a italic q right parenthesis number space number space number space number space s number space number space number space number space number space number space number space s number space number space number space number space number space number space number space 2 s


Nilai O H to the power of minus sign dapat ditentukan sebagai berikut.
 

table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell 14 minus sign pH end cell row pOH equals cell 14 minus sign open parentheses 9 plus log space 4 close parentheses end cell row pOH equals cell 5 minus sign log space 4 end cell row blank blank blank row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 10 to the power of negative sign pOH end exponent end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 10 to the power of negative sign left parenthesis 5 minus sign log space 4 right parenthesis end exponent end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 4 cross times 10 to the power of negative sign 5 end exponent end cell end table


Ingat! Bagian O H to the power of minus sign adalah 2s. Persamaan K subscript sp dari X open parentheses O H close parentheses subscript 2 menjadi seperti berikut.
 

table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp space X open parentheses O H close parentheses subscript 2 end cell equals cell open square brackets X to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared end cell row cell K subscript sp space X open parentheses O H close parentheses subscript 2 end cell equals cell open square brackets s close square brackets open square brackets 2 s close square brackets squared end cell row cell K subscript sp space X open parentheses O H close parentheses subscript 2 end cell equals cell open square brackets 1 half cross times 4 cross times 10 to the power of negative sign 5 end exponent close square brackets open square brackets 4 cross times 10 to the power of negative sign 5 end exponent close square brackets squared end cell row cell K subscript sp space X open parentheses O H close parentheses subscript 2 end cell equals cell open square brackets 2 cross times 10 to the power of negative sign 5 space end exponent close square brackets space left square bracket 16 cross times 10 to the power of negative sign 10 end exponent right square bracket end cell row cell K subscript sp space X open parentheses O H close parentheses subscript 2 end cell equals cell 32 cross times 10 to the power of negative sign 15 end exponent end cell row cell K subscript sp X open parentheses O H close parentheses subscript 2 end cell equals cell 3 comma 2 cross times 10 to the power of negative sign 14 end exponent end cell end table


Jadi, jawaban yang benar adalah A.

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