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15,2 g campuran basa KOH dan NaOH dilarutkan dalam air hingga 250 mL. Kemudian, 25 mL larutan tersebut dititrasi dengan 100 mL larutan HCl 0,3 M. Jika Mr NaOH = 40 dan Mr KOH = 56, tentukanlah massa setiap basa tersebut!

Pertanyaan

15,2 g campuran basa KOH dan NaOH dilarutkan dalam air hingga 250 mL. Kemudian, 25 mL larutan tersebut dititrasi dengan 100 mL larutan HCl 0,3 M. Jika Mr NaOH = 40 dan Mr KOH = 56, tentukanlah massa setiap basa tersebut!space

Pembahasan Soal:

m Campuran (KOH dan NaOH)= 15,2 gram

Volume larutan = 250 ml = 0,25 L

Volume campuran pentitrasian = 25 ml

Volume larutan HCl = 100 ml

Molaritas HCl = 0,3 M

Mr NaOH = 40

Mr KOH = 56

menentukan molaritas campuran :

M cross times V space space space space space space space equals space M cross times V space M cross times 25 space ml space equals space 0 comma 3 M cross times 100 space ml space M space space space space space space space space space space space equals space fraction numerator 0 comma 3 M cross times 100 space ml over denominator 25 space ml end fraction M space space space space space space space space space space space equals 30 over 25 M space space space space space space space space space space space equals 1 comma 2 space M 

n mol Campuran :

n equals space M cross times space V space space equals space 1 comma 2 space M cross times 0 comma 25 space L space space equals space 0 comma 3 space mol space

mol KOH :
space n equals fraction numerator M subscript r space K O H over denominator M subscript r space total end fraction cross times mol space total space space equals space fraction numerator 56 over denominator left parenthesis 40 plus 56 right parenthesis end fraction cross times 0 comma 3 space mol space space equals 0 comma 175 space mol 

mol NaOH :

space n equals fraction numerator M subscript r space Na O H over denominator M subscript r space total end fraction cross times mol space total space space equals space fraction numerator 40 over denominator left parenthesis 40 plus 56 right parenthesis end fraction cross times 0 comma 3 space mol space space equals 0 comma 125 space mol 

mencari massa masing - masing basa :

massa KOH :
massa space equals fraction numerator n space K O H over denominator n space total end fraction cross times massa space total massa space equals fraction numerator 0 comma 175 space mol over denominator 0 comma 3 space mol end fraction cross times 15 comma 2 space gram massa space equals space 8 comma 87 space gram 

massa NaOH :
massa space equals space fraction numerator n space Na O H over denominator n space total end fraction cross times massa space total massa space equals space fraction numerator 0 comma 125 space mol over denominator 0 comma 3 space mol end fraction cross times 15 comma 2 space gram massa space equals 6 comma 33 space gram

Jadi, massa basa KOH = 88,7 gram dan massa basa NaOH = 6,33 gram.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 27 April 2021

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