Pertanyaan

x → ∞ lim ( 2 x − 3 ) − 4 x 2 − p x = 4 , tentukan nilai ?

$x \to \infty lim (2 x - 3) - 4 x^{2} - p x = 4$ , tentukan nilai $p$ ?

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Klaim

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

nilai adalah .

nilai

adalah

Pembahasan

Jadi,nilai adalah .

$table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow infinity of space left parenthesis 2 x minus 3 right parenthesis minus square root of 4 x squared minus p x end root end cell equals 4 row blank blank blank row cell limit as x rightwards arrow infinity of space square root of left parenthesis 2 x minus 3 right parenthesis squared end root minus square root of 4 x squared minus p x end root end cell equals cell limit as x rightwards arrow infinity of square root of 4 x squared minus 6 x plus 9 end root minus square root of 4 x squared minus p x end root end cell row cell limit as x rightwards arrow infinity of space square root of a x squared plus b x plus c end root minus square root of p x squared plus q x plus r end root end cell equals L row cell Karna space a end cell equals cell p space maka space end cell row L equals cell fraction numerator b minus q over denominator 2 square root of a end fraction end cell row b equals cell negative 6 end cell row q equals cell negative p end cell row a equals 4 row L equals 4 row L equals cell fraction numerator negative 6 minus p over denominator 2 square root of 4 end fraction end cell row 4 equals cell fraction numerator negative 6 minus p over denominator 2 times 2 end fraction end cell row 4 equals cell fraction numerator negative 6 minus p over denominator 4 end fraction end cell row cell 4 cross times 4 end cell equals cell negative 6 minus p end cell row 16 equals cell negative 6 minus p end cell row p equals cell negative 6 minus 16 end cell row p equals cell negative 22 end cell end table$

Jadi, nilai adalah negative 22 .