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Pertanyaan

x → 0 lim ​ sin x tan 3 x 1 − cos 2 2 x ​ = ...

= ...

  1. 1 third

  2. 2 over 3

  3. 1

  4. 4 over 3

  5. 5 over 3

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H. Eka

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

Jawaban terverifikasi

Pembahasan

limit as x rightwards arrow 0 of space fraction numerator 1 minus cos squared space 2 x space over denominator sin space x space tan space 3 x end fraction space equals space limit as x rightwards arrow 0 of space fraction numerator sin squared space 2 x space over denominator sin space x space tan space 3 x end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space limit as x rightwards arrow 0 of space fraction numerator sin space 2 x space sin space 2 x space over denominator sin space x space tan space 3 x end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space limit as x rightwards arrow 0 of space fraction numerator sin space 2 x space over denominator sin space x space end fraction space fraction numerator sin space 2 x over denominator tan space 3 x end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 2 space 2 over 3 space equals space 4 over 3 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space

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x → 0 lim ​ x 2 sin 3 x tan 2 x ​ = ....

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