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x → 0 lim ​ 1 − cos 4 x 4 x 2 ​ = ....

....

  1. 0,125

  2. 0,25

  3. 0,5

  4. 0,75

  5. 1

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H. Eka

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

Jawaban terverifikasi

Pembahasan

begin mathsize 14px style limit as x rightwards arrow 0 of space fraction numerator 4 x squared over denominator 1 minus cos space 4 x end fraction equals space limit as x rightwards arrow 0 of space fraction numerator 4 x squared over denominator 1 minus open parentheses 1 minus 2 sin squared space 2 x close parentheses end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space space limit as x rightwards arrow 0 of space fraction numerator 4 x squared over denominator 2 space sin squared space 2 x end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space limit as x rightwards arrow 0 of space fraction numerator 4 x over denominator 2 space sin space 2 x end fraction space. space fraction numerator x over denominator sin space 2 x end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 1. space 1 half space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 1 half equals 0 comma 5 end style

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x → 0 lim ​ x 2 sin 3 x tan 2 x ​ = ....

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