Pertanyaan

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$begin mathsize 14px style limit as straight x rightwards arrow 3 of invisible function application fraction numerator sin invisible function application open parentheses 3 straight x minus 9 close parentheses over denominator square root of straight x plus 1 end root minus 2 end fraction equals end style$ ....

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A. Abdul

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Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

Pembahasan

Perhatikan bahwa Jadi, jawaban yang tepat adalah B.

Perhatikan bahwa

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as straight x rightwards arrow 3 of invisible function application fraction numerator sin invisible function application open parentheses 3 straight x minus 9 close parentheses over denominator square root of straight x plus 1 end root minus 2 end fraction end cell row blank equals cell limit as straight x rightwards arrow 3 of invisible function application open parentheses fraction numerator sin invisible function application open parentheses 3 straight x minus 9 close parentheses over denominator square root of straight x plus 1 end root minus 2 end fraction times fraction numerator square root of straight x plus 1 end root plus 2 over denominator square root of straight x plus 1 end root plus 2 end fraction close parentheses end cell row blank equals cell limit as straight x rightwards arrow 3 of invisible function application fraction numerator sin invisible function application open parentheses 3 straight x minus 9 close parentheses open parentheses square root of straight x plus 1 end root plus 2 close parentheses over denominator open parentheses straight x plus 1 close parentheses minus 4 end fraction end cell row blank equals cell limit as straight x rightwards arrow 3 of invisible function application fraction numerator sin invisible function application open parentheses 3 straight x minus 9 close parentheses open parentheses square root of straight x plus 1 end root plus 2 close parentheses over denominator straight x minus 3 end fraction end cell row blank equals cell limit as straight x rightwards arrow 3 of invisible function application open parentheses fraction numerator sin invisible function application open parentheses 3 straight x minus 9 close parentheses open parentheses square root of straight x plus 1 end root plus 2 close parentheses over denominator straight x minus 3 end fraction times 3 over 3 close parentheses end cell row blank equals cell limit as straight x rightwards arrow 3 of invisible function application fraction numerator 3 sin invisible function application open parentheses 3 straight x minus 9 close parentheses open parentheses square root of straight x plus 1 end root plus 2 close parentheses over denominator 3 straight x minus 9 end fraction end cell row blank equals cell limit as straight x rightwards arrow 3 of invisible function application 3 times limit as straight x rightwards arrow 3 of invisible function application fraction numerator sin invisible function application open parentheses 3 straight x minus 9 close parentheses over denominator 3 straight x minus 9 end fraction times limit as straight x rightwards arrow 3 of invisible function application open parentheses square root of straight x plus 1 end root plus 2 close parentheses end cell row blank equals cell 3 times 1 times open parentheses square root of 3 plus 1 end root plus 2 close parentheses end cell row blank equals cell 3 times 1 times open parentheses square root of 4 plus 2 close parentheses end cell row blank equals cell 3 times 1 times open parentheses 2 plus 2 close parentheses end cell row blank equals cell 3 times 1 times 4 end cell row blank equals 12 end table end style$

Jadi, jawaban yang tepat adalah B.