Pertanyaan

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$begin mathsize 14px style limit as straight x rightwards arrow 3 of invisible function application fraction numerator sin invisible function application open parentheses 3 straight x minus 9 close parentheses over denominator square root of straight x plus 1 end root minus 2 end fraction equals end style$ ....

8 dari 10 siswa nilainya naik

dengan paket belajar pilihan

Habis dalam

Klaim

A. Abdul

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

Pembahasan

Perhatikan bahwa Jadi, jawaban yang tepat adalah B.

Perhatikan bahwa

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as straight x rightwards arrow 3 of invisible function application fraction numerator sin invisible function application open parentheses 3 straight x minus 9 close parentheses over denominator square root of straight x plus 1 end root minus 2 end fraction end cell row blank equals cell limit as straight x rightwards arrow 3 of invisible function application open parentheses fraction numerator sin invisible function application open parentheses 3 straight x minus 9 close parentheses over denominator square root of straight x plus 1 end root minus 2 end fraction times fraction numerator square root of straight x plus 1 end root plus 2 over denominator square root of straight x plus 1 end root plus 2 end fraction close parentheses end cell row blank equals cell limit as straight x rightwards arrow 3 of invisible function application fraction numerator sin invisible function application open parentheses 3 straight x minus 9 close parentheses open parentheses square root of straight x plus 1 end root plus 2 close parentheses over denominator open parentheses straight x plus 1 close parentheses minus 4 end fraction end cell row blank equals cell limit as straight x rightwards arrow 3 of invisible function application fraction numerator sin invisible function application open parentheses 3 straight x minus 9 close parentheses open parentheses square root of straight x plus 1 end root plus 2 close parentheses over denominator straight x minus 3 end fraction end cell row blank equals cell limit as straight x rightwards arrow 3 of invisible function application open parentheses fraction numerator sin invisible function application open parentheses 3 straight x minus 9 close parentheses open parentheses square root of straight x plus 1 end root plus 2 close parentheses over denominator straight x minus 3 end fraction times 3 over 3 close parentheses end cell row blank equals cell limit as straight x rightwards arrow 3 of invisible function application fraction numerator 3 sin invisible function application open parentheses 3 straight x minus 9 close parentheses open parentheses square root of straight x plus 1 end root plus 2 close parentheses over denominator 3 straight x minus 9 end fraction end cell row blank equals cell limit as straight x rightwards arrow 3 of invisible function application 3 times limit as straight x rightwards arrow 3 of invisible function application fraction numerator sin invisible function application open parentheses 3 straight x minus 9 close parentheses over denominator 3 straight x minus 9 end fraction times limit as straight x rightwards arrow 3 of invisible function application open parentheses square root of straight x plus 1 end root plus 2 close parentheses end cell row blank equals cell 3 times 1 times open parentheses square root of 3 plus 1 end root plus 2 close parentheses end cell row blank equals cell 3 times 1 times open parentheses square root of 4 plus 2 close parentheses end cell row blank equals cell 3 times 1 times open parentheses 2 plus 2 close parentheses end cell row blank equals cell 3 times 1 times 4 end cell row blank equals 12 end table end style$

Jadi, jawaban yang tepat adalah B.