Pertanyaan

x → 4 lim 13 − x − x + 5 16 − x 2 = ....

$x \to 4 lim \frac{16 - x ^{2}}{13 - x - x + 5} =$ ....

8 dari 10 siswa nilainya naik

dengan paket belajar pilihan

Habis dalam

Klaim

A. Abdul

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah D.

Pembahasan

Perhatikan bahwa Jadi, jawaban yang tepat adalah D.

Perhatikan bahwa

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as straight x rightwards arrow 4 of invisible function application fraction numerator 16 minus straight x squared over denominator square root of 13 minus straight x end root minus square root of straight x plus 5 end root end fraction end cell row blank equals cell limit as straight x rightwards arrow 4 of invisible function application fraction numerator open parentheses 4 plus straight x close parentheses open parentheses 4 minus straight x close parentheses over denominator square root of 13 minus straight x end root minus square root of straight x plus 5 end root end fraction end cell row blank equals cell limit as straight x rightwards arrow 4 of invisible function application open parentheses fraction numerator open parentheses 4 plus straight x close parentheses open parentheses 4 minus straight x close parentheses over denominator square root of 13 minus straight x end root minus square root of straight x plus 5 end root end fraction times fraction numerator square root of 13 minus straight x end root plus square root of straight x plus 5 end root over denominator square root of 13 minus straight x end root plus square root of straight x plus 5 end root end fraction close parentheses end cell row blank equals cell limit as straight x rightwards arrow 4 of invisible function application fraction numerator open parentheses 4 plus straight x close parentheses open parentheses 4 minus straight x close parentheses open parentheses square root of 13 minus straight x end root plus square root of straight x plus 5 end root close parentheses over denominator open parentheses 13 minus straight x close parentheses minus open parentheses straight x plus 5 close parentheses end fraction end cell row blank equals cell limit as straight x rightwards arrow 4 of invisible function application fraction numerator open parentheses 4 plus straight x close parentheses open parentheses 4 minus straight x close parentheses open parentheses square root of 13 minus straight x end root plus square root of straight x plus 5 end root close parentheses over denominator 8 minus 2 straight x end fraction end cell row blank equals cell limit as straight x rightwards arrow 4 of invisible function application fraction numerator open parentheses 4 plus straight x close parentheses open parentheses 4 minus straight x close parentheses open parentheses square root of 13 minus straight x end root plus square root of straight x plus 5 end root close parentheses over denominator 2 open parentheses 4 minus straight x close parentheses end fraction end cell row blank equals cell limit as straight x rightwards arrow 4 of invisible function application fraction numerator open parentheses 4 plus straight x close parentheses open parentheses square root of 13 minus straight x end root plus square root of straight x plus 5 end root close parentheses over denominator 2 end fraction end cell row blank equals cell fraction numerator open parentheses 4 plus 4 close parentheses open parentheses square root of 13 minus 4 end root plus square root of 4 plus 5 end root close parentheses over denominator 2 end fraction end cell row blank equals cell fraction numerator open parentheses 8 close parentheses open parentheses square root of 9 plus square root of 9 close parentheses over denominator 2 end fraction end cell row blank equals cell 4 open parentheses 3 plus 3 close parentheses end cell row blank equals cell 4 open parentheses 6 close parentheses end cell row blank equals 24 end table end style$

Jadi, jawaban yang tepat adalah D.