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Pertanyaan

fraction numerator 5 to the power of negative 3 end exponent times 2 to the power of 4 over denominator 2 squared minus 5 end fraction equals...

Pembahasan Soal:

Perlu diingat bahwa:

a to the power of negative m end exponent equals 1 over a to the power of m comma space a not equal to 0

Dengan menggunakan sifat di atas, maka diperoleh:

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 5 to the power of negative 3 end exponent times 2 to the power of 4 over denominator 2 squared minus 5 end fraction end cell equals cell fraction numerator 2 to the power of 4 over denominator 5 cubed open parentheses 2 squared minus 5 close parentheses end fraction end cell row blank equals cell fraction numerator 16 over denominator 125 open parentheses 4 minus 5 close parentheses end fraction end cell row blank equals cell fraction numerator 16 over denominator 125 open parentheses negative 1 close parentheses end fraction end cell row blank equals cell negative 16 over 125 end cell end table


Dengan demikian, hasil dari fraction numerator 5 to the power of negative 3 end exponent times 2 to the power of 4 over denominator 2 squared minus 5 end fraction adalah negative 16 over 125.

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

S. Nur

Terakhir diupdate 13 Agustus 2021

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Bentuk sederhana dari ⎝⎛​x31​y32​z31​x32​y34​z−31​​⎠⎞​6 adalah ...

Pembahasan Soal:

Ingat!

Sifat bilangan berpangkat:

  • am:an=amn 
  • (am)n=am×n 
  • an=an1 

x31y32z31x32y34z316======(x3231y3432z3131)6(x31y32z32)6(x31)6(y32)6(z32)6x31×6y32×6z32×6x2y4z4z4x2y4 

Dengan demikian, bentuk sederhana dari x31y32z31x32y34z316 adalah z4x2y4.

0

Roboguru

Sederhanakan bentuk operasi perpangkatan berikut ini. d.

Pembahasan Soal:

Ingat :

straight a to the power of negative straight n end exponent equals 1 over straight a to the power of straight n  

Maka, bentuk sederhananya adalah

table attributes columnalign right center left columnspacing 0px end attributes row cell straight m cubed plus 4 over straight m to the power of negative 3 end exponent end cell equals cell straight m cubed plus 4 straight m cubed end cell row blank equals cell 5 straight m cubed end cell end table

1

Roboguru

Diketahui dan . Nilai dari  adalah ....

Pembahasan Soal:

Ingat bahwa undefined, begin mathsize 14px style a to the power of negative n end exponent equals 1 over a to the power of n end style, dan undefined.

Selanjutnya, perhatikan perhitungan berikut!

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell p divided by q end cell equals cell fraction numerator x to the power of negative 2 end exponent y plus y to the power of negative 3 end exponent over denominator 3 x y end fraction divided by fraction numerator 13 x cubed over denominator y to the power of 4 end fraction space end cell row blank equals cell fraction numerator x to the power of negative 2 end exponent y plus y to the power of negative 3 end exponent over denominator 3 x y end fraction cross times fraction numerator y to the power of 4 over denominator 13 x cubed end fraction end cell row blank equals cell fraction numerator left parenthesis x to the power of negative 2 end exponent y plus y to the power of negative 3 end exponent right parenthesis y to the power of 4 over denominator 3 x y times 13 x cubed end fraction end cell row blank equals cell fraction numerator x to the power of negative 2 end exponent y to the power of 1 plus 4 end exponent plus y to the power of negative 3 plus 4 end exponent over denominator 39 x to the power of 1 plus 3 end exponent y end fraction end cell row blank equals cell fraction numerator x to the power of negative 2 end exponent y to the power of 5 plus y over denominator 39 x to the power of 4 y end fraction end cell row blank equals cell fraction numerator begin display style y to the power of 5 over x squared end style plus y over denominator 39 x to the power of 4 y end fraction end cell row blank equals cell fraction numerator begin display style fraction numerator y to the power of 5 plus x squared y over denominator x squared end fraction end style over denominator 39 x to the power of 4 y end fraction end cell row blank equals cell fraction numerator y to the power of 5 plus x squared y over denominator x squared end fraction divided by fraction numerator 39 x to the power of 4 y over denominator 1 end fraction end cell row blank equals cell fraction numerator y to the power of 5 plus x squared y over denominator x squared end fraction cross times fraction numerator 1 over denominator 39 x to the power of 4 y end fraction end cell row blank equals cell fraction numerator y to the power of 5 plus x squared y over denominator 39 x to the power of 2 plus 4 end exponent y end fraction end cell row blank equals cell fraction numerator y to the power of 5 plus x squared y over denominator 39 x to the power of 6 y end fraction end cell end table end style

Jadi, jawaban yang tepat adalah B.

2

Roboguru

= ....

Pembahasan Soal:

Ingat bahwa Error converting from MathML to accessible text. , maka

Error converting from MathML to accessible text.    

Jadi, jawaban yang tepat adalah D.

0

Roboguru

Hasil dari adalah ....

Pembahasan Soal:

4 to the power of negative 2 end exponent space plus space 2 to the power of negative 4 end exponent space equals space 1 over 4 squared plus 1 over 2 to the power of 4  space space space space space space space space space space space space space space space space space space space space space equals space 1 over 16 plus 1 over 16  space space space space space space space space space space space space space space space space space space space space space equals space 2 over 16  space space space space space space space space space space space space space space space space space space space space space equals space 1 over 8

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Roboguru

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