Salwa R
26 Maret 2024 21:27
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Salwa R
26 Maret 2024 21:27
Pertanyaan
tolongg yya
11
2
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Sumber W
Community
Level 72
27 Maret 2024 03:52
1. Hambatan paralel
1/Rp = 1/x + 1/x + 1/x
1/Rp = 3/x
Rp = x/3 ohm
Hambatan total (Rtotal )
Rtotal = Rp + x
= x/3 + x
= (1/3 + 3/3) x
= 4/3 x
2. Hambatan paralel
1/Rp = 1/(x + x) + 1/x
1/Rp = 1/(2x) + 1/x
= 1/(2x) + 2/(2x)
= 3/(2x)
Rp = 2x/3 ohm
Hambatan total (Rtotal )
Rtotal = Rp + x
= 2x/3 + x
= (2/3 + 3/3) x
= 5/3 x
3. Hambatan paralel
1/Rp = 1/(x + x) + 1/(x + x)
1/Rp = 1/(2x) + 1/(2x)
1/Rp = 2/(2x)
Rp = 2x/2 = x ohm
4. Hambatan paralel
1/Rp = 1/x + 1/x
1/Rp = 2/x
Rp = x/2 ohm
Hambatan total (Rtotal )
Rtotal = Rp + x
= x/2 + x + x
= (1/2 + 2/2 + 2/2) x
= 5/2 x
Nilai hambatan pengganti :
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Raissa F
Level 6
27 Maret 2024 04:44
anggap nilai R = 2
1. R total = 1/(1/2 + 1/2 + 1/2) + 2
R total = 2/3+6/3
R total = 8/3 = 2,67
2. R total = 1/(1/4+1/2) + 2
R total = 4/3 + 6/3
R total = 10/3 = 3,33
3. R total = 1/(1/4+1/4)
R total = 4/2
R total = 2
4. R total = 2 + 1/(1/2+1/2) + 2
R total = 2 + 1 + 2 = 5
R terbesar adalah 4
R terkecil adalah 3
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