Salwa R
26 Maret 2024 21:27
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Salwa R
26 Maret 2024 21:27
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Sumber W
Community
27 Maret 2024 03:52
<p>1. Hambatan paralel</p><p> 1/Rp = 1/x + 1/x + 1/x</p><p> 1/Rp = 3/x</p><p> Rp = x/3 ohm</p><p> </p><p> Hambatan total (R<sub>total</sub> )</p><p> R<sub>total</sub> = Rp + x</p><p> = x/3 + x</p><p> = (1/3 + 3/3) x</p><p> = 4/3 x</p><p> </p><p>2. Hambatan paralel</p><p> 1/Rp = 1/(x + x) + 1/x</p><p> 1/Rp = 1/(2x) + 1/x</p><p> = 1/(2x) + 2/(2x)</p><p> = 3/(2x)</p><p> Rp = 2x/3 ohm</p><p> </p><p> Hambatan total (R<sub>total</sub> )</p><p> R<sub>total</sub> = Rp + x</p><p> = 2x/3 + x</p><p> = (2/3 + 3/3) x</p><p> = 5/3 x</p><p> </p><p>3. Hambatan paralel</p><p> 1/Rp = 1/(x + x) + 1/(x + x)</p><p> 1/Rp = 1/(2x) + 1/(2x)</p><p> 1/Rp = 2/(2x)</p><p> Rp = 2x/2 = x ohm</p><p> </p><p>4. Hambatan paralel</p><p> 1/Rp = 1/x + 1/x </p><p> 1/Rp = 2/x</p><p> Rp = x/2 ohm</p><p> </p><p> Hambatan total (R<sub>total</sub> )</p><p> R<sub>total</sub> = Rp + x</p><p> = x/2 + x + x</p><p> = (1/2 + 2/2 + 2/2) x</p><p> = 5/2 x</p><p> </p><p>Nilai hambatan pengganti :</p><ul><li>Paling besar adalah nomor 4</li><li>Paling kecil adalah nomor 3</li></ul><p> </p>
1. Hambatan paralel
1/Rp = 1/x + 1/x + 1/x
1/Rp = 3/x
Rp = x/3 ohm
Hambatan total (Rtotal )
Rtotal = Rp + x
= x/3 + x
= (1/3 + 3/3) x
= 4/3 x
2. Hambatan paralel
1/Rp = 1/(x + x) + 1/x
1/Rp = 1/(2x) + 1/x
= 1/(2x) + 2/(2x)
= 3/(2x)
Rp = 2x/3 ohm
Hambatan total (Rtotal )
Rtotal = Rp + x
= 2x/3 + x
= (2/3 + 3/3) x
= 5/3 x
3. Hambatan paralel
1/Rp = 1/(x + x) + 1/(x + x)
1/Rp = 1/(2x) + 1/(2x)
1/Rp = 2/(2x)
Rp = 2x/2 = x ohm
4. Hambatan paralel
1/Rp = 1/x + 1/x
1/Rp = 2/x
Rp = x/2 ohm
Hambatan total (Rtotal )
Rtotal = Rp + x
= x/2 + x + x
= (1/2 + 2/2 + 2/2) x
= 5/2 x
Nilai hambatan pengganti :
- Paling besar adalah nomor 4
- Paling kecil adalah nomor 3
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Raissa F
27 Maret 2024 04:44
<p>anggap nilai R = 2</p><p> </p><p>1. R total = 1/(1/2 + 1/2 + 1/2) + 2</p><p>R total = 2/3+6/3 </p><p>R total = 8/3 = 2,67</p><p> </p><p>2. R total = 1/(1/4+1/2) + 2</p><p>R total = 4/3 + 6/3</p><p>R total = 10/3 = 3,33</p><p> </p><p>3. R total = 1/(1/4+1/4)</p><p>R total = 4/2</p><p>R total = 2</p><p> </p><p>4. R total = 2 + 1/(1/2+1/2) + 2</p><p>R total = 2 + 1 + 2 = 5</p><p> </p><p>R terbesar adalah 4</p><p>R terkecil adalah 3</p>
anggap nilai R = 2
1. R total = 1/(1/2 + 1/2 + 1/2) + 2
R total = 2/3+6/3
R total = 8/3 = 2,67
2. R total = 1/(1/4+1/2) + 2
R total = 4/3 + 6/3
R total = 10/3 = 3,33
3. R total = 1/(1/4+1/4)
R total = 4/2
R total = 2
4. R total = 2 + 1/(1/2+1/2) + 2
R total = 2 + 1 + 2 = 5
R terbesar adalah 4
R terkecil adalah 3
· 0.0 (0)
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