tolong kak

<p>Misalkan a = 1/(2x+5y+3) dan b = 1/(3x-2y-2), sistem persamaan berubah menjadi:</p><p>3a - 6b = 1/2 |x2| 6a - 12b = 1</p><p>&nbsp; a + 3b = 1 &nbsp; &nbsp; |x4|<u> 4a + 12b = 4&nbsp;</u> +</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;10a &nbsp;= 5</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; a = 1/2 -&gt; 2x+5y+3 = 2...(1)</p><p>Akibatnya:</p><p>a + 3b = 1</p><p>1/2 + 3b = 1</p><p>3b = 1/2</p><p>b = 1/6 -&gt; 3x-2y-2 = 6...(2)</p><p>&nbsp;</p><p>Dengan demikian:</p><p>2x+5y+3 = 2 -&gt; 2x + 5y = -1 |x3| 6x + 15y = -3</p><p>3x-2y-2 = 6 &nbsp; -&gt; 3x &nbsp;- 2y = 8 &nbsp;|x2|<u> 6x &nbsp;- &nbsp; &nbsp;4y = 16</u> -</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;19y = -19</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; y = -1</p><p>Akibatnya:</p><p>3x - 2y - 2 = 6</p><p>3x - 2(-1) - 2 = 6</p><p>3x + 2 - 2 = 6</p><p>3x = 6</p><p>x = 2</p><p>&nbsp;</p><p>Akhirnya diperoleh HP untuk sistem persamaan ini adalah <strong>{(x,y): (2,-1)}</strong></p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;</p>