Tolong dongg ini caranya kyk gimana

<p>{<br>Penjelasan:&nbsp;<br>Langkah 1: Menggunakan sifat logaritma, kita dapat menyederhanakan ekspresi di sisi kiri persamaan.&nbsp;<br>Langkah 2: Menggunakan sifat logaritma lainnya, kita dapat menyederhanakan ekspresi di sisi kanan persamaan.&nbsp;<br>Langkah 3: Menggabungkan kedua ekspresi yang disederhanakan, kita mendapatkan persamaan baru.&nbsp;<br>Langkah 4: Menyelesaikan persamaan baru untuk x/y.&nbsp;<br>Jawaban:&nbsp;<br>x/y=-2/11 (E)<br>Penjelasan:<br>Langkah 1: Menggunakan sifat logaritma, kita dapat menyederhanakan ekspresi di sisi kiri persamaan.&nbsp;<br>$2log(a^{3/2}b^{7/2}c^{11/2})-2log(bc) = 2log(a^{3/2}b^{7/2}c^{11/2}/bc) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{</p>