Qiki S
10 Juli 2024 16:48
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Qiki S
10 Juli 2024 16:48
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Tolong dongg ini caranya kyk gimana
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Shendika P
10 Juli 2024 19:41
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Penjelasan:
Langkah 1: Menggunakan sifat logaritma, kita dapat menyederhanakan ekspresi di sisi kiri persamaan.
Langkah 2: Menggunakan sifat logaritma lainnya, kita dapat menyederhanakan ekspresi di sisi kanan persamaan.
Langkah 3: Menggabungkan kedua ekspresi yang disederhanakan, kita mendapatkan persamaan baru.
Langkah 4: Menyelesaikan persamaan baru untuk x/y.
Jawaban:
x/y=-2/11 (E)
Penjelasan:
Langkah 1: Menggunakan sifat logaritma, kita dapat menyederhanakan ekspresi di sisi kiri persamaan.
$2log(a^{3/2}b^{7/2}c^{11/2})-2log(bc) = 2log(a^{3/2}b^{7/2}c^{11/2}/bc) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{7/2}c^{11/2}/b c) = 2log(a^{3/2}b^{
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Qiki S
11 Juli 2024 07:58
spam bgt ya
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