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<p><strong>Cari pH masing masing:</strong></p><p>a) NaOH (basa kuat):<br>&nbsp; [OH-] = C = 0,1 M<br>&nbsp; pOH = -log(0,1) = 1<br>&nbsp; pH = 14 - 1 = 13</p><p>b) CH3COOH (asam lemah):<br>&nbsp; [H+] = √(Ka × C) = √(10^-5 × 0,1)<br>&nbsp; &nbsp; &nbsp; &nbsp; = √(10^-6) = 10^-3<br>&nbsp; pH = -log(10^-3) = 3<br>&nbsp;</p><p><strong>Setelah dicampur</strong></p><p>Hitung mol:<br>nNaOH = 0,1 × 0,100 = 0,010 mol<br>nCH3COOH = 0,1 × 0,100 = 0,010 mol</p><p>Reaksi:<br>NaOH + CH3COOH → CH3COONa + H2O</p><p>Karena mol sama → habis sempurna → tersisa garam CH3COONa<br>&nbsp;</p><p><strong>Cari konsen garam:</strong></p><p>ngaram = 0,010 mol<br>Vtotal = 100 mL + 100 mL = 200 mL = 0,200 L</p><p>Cgaram = ngaram / Vtotal<br>&nbsp; &nbsp; &nbsp; &nbsp;= 0,010 / 0,200<br>&nbsp; &nbsp; &nbsp; &nbsp;= 0,050 M</p><p><strong>Cari hdrlisis garamnya (Ph gara):</strong></p><p>Kb = Kw / Ka = 10^-14 / 10^-5 = 10^-9<br>[OH-] = √(Kb × Cgaram)<br>&nbsp; &nbsp; &nbsp;= √(10^-9 × 0,05)<br>&nbsp; &nbsp; &nbsp;= √(5×10^-11)<br>&nbsp; &nbsp; &nbsp;≈ 7,1×10^-6 M</p><p>pOH = -log(7,1×10^-6) ≈ 5,15<br>pH = 14 - 5,15 = 8,85</p><p>&nbsp;</p><p>Jadi, pH NaOH 0,1 M sebelum dicampur adalah 13<br>pH CH3COOH 0,1 M sebelum dicampur adalah 3<br>pH campuran setelah dicampur adalah 8,85<br><br>&nbsp;</p><p>&nbsp;</p>