Tolong dibantu ya kak!! Sesuaikan dengan cara kerjanya! Terimakasih..... Semoga cepat di jawab yaa!!

<p>Harga 1 coklat = <strong>Rp 1.000</strong>, harga 1 permen = <strong>Rp 1.500</strong>, harga 1 kue = <strong>Rp 2.000</strong>.</p><p>&nbsp;</p><p><strong>Diketahui : </strong>(x = coklat), (y = permen), (z = kue)</p><p>Andi membeli 2 coklat, 4 permen, dan 5 kue totalnya Rp 18.000.</p><p>2x + 4y + 5z = 18.000 ... (1)</p><p>Bela membeli 1 coklat, 3 Permen, dan 2 kue totanya Rp 9.500.&nbsp;</p><p>x + 3y + 2z = 9.500 ... (2)</p><p>Sedangkan Sindi membeli 3 coklat, 2 Permen dan 1 kue totalnya Rp 8.000.&nbsp;</p><p>3x + 2y + z = 8.000 ... (3)</p><p><strong>Ditanya : </strong>harga masing untuk coklat, permen, dan kue = ... ?</p><p><strong>Dijawab :</strong></p><p>Mengurangi pada persamaan (1) dan (2) untuk eliminasi nilai x :</p><p>2x + 4y + 5z = 18.000 |1×| &nbsp;2x + 4y + 5z = 18.000</p><p>&nbsp; x + 3y + 2z = 9.500 &nbsp; |2×| &nbsp;<u>2x + 6y + 4z = 19.000</u> –</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 0 - 2y + z = -1.000</p><p>-2y + z = -1.000 ... (4)</p><p>Mengurangi pada persamaan (2) dan (3) untuk eliminasi nilai x :</p><p>x + 3y + 2z = 9.500 |3×| 3x + 9y + 6z = 28.500</p><p>3x + 2y + z = 8.000 |1×|&nbsp;<u> &nbsp;3x + 2y + z = 8.000 &nbsp;</u> &nbsp;–</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;0 + 7y + 5z = 20.500</p><p>7y + 5z = 20.500 ... (5)</p><p>Mengurangi pada persamaan (4) dan (5) untuk eliminasi nilai z :</p><p>&nbsp;-2y + z = -1.000 &nbsp;|5×| -10y + 5z = -5.000</p><p>7y + 5z = 20.500 |1×|&nbsp;<u> &nbsp; &nbsp;7y + 5z = 20.500</u> &nbsp;–</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;-17y + 0 = -25.500</p><p>17y = 25.000</p><p>&nbsp; &nbsp;y = ^(25.000)/₁₇ = 1.500</p><p>Maka <strong>harga 1 permen adalah Rp 1.500</strong></p><p>&nbsp;</p><p>Subtitusi y = 1.500 ke persamaan (4) untuk mencari nilai z :</p><p>-2y + z = -1.000</p><p>-2(1.500) + z = -1.000</p><p>&nbsp; &nbsp; &nbsp;-3.000 + z = -1.000</p><p>z = -1.000 + 3.000 = 2.000</p><p>Maka <strong>harga 1 kue adalah Rp 2.000</strong></p><p>&nbsp;</p><p>Subtitusi y = 1.500 dan z = 2.000 ke persamaan (2) untuk mencari nilai x :</p><p>x + 3y + 2z = 9.500</p><p>x + 3(1.500) + 2(2.000) = 9.500</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; x + 4.500 + 4.000 = 9.000</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; x + 8.500 = 9.500</p><p>x = 9.500 - 8.500 = 1.000</p><p>Maka <strong>harga 1 coklat adalah Rp 1.000</strong></p><p>&nbsp;</p><p>Selesai :D 🙏</p>