Tolong bantuannya menggunakan caranya

transformasi geometri translasi T1(x1, y1) = (a, 2) lanjut T2(x2, y2) = (-2, b) x' = x + x1 + x2 x' = x + a + (-2) x = x' - a + 2 y' = y + y1 + y2 y' = y + 2 + b y = y' - 2 - b Hasil translasi : y = 3x² + 5x + 6 y' - 2 - b = 3(x' - a + 2)² + 5(x' - a + 2) + 6 y = 3(x + (2 - a))² + 5x - 5a + 10 + 6 + 2 + b y = 3(x² + 2(2 - a)x) + (2 - a)²) + 5x - 5a + b + 18 y = 3x² + 6(2 - a)x + 3(2 - a)² + 5x - 5a + b + 18 y = 3x² + (12 - 6a + 5)x + 3(2 - a)² - 5a + b + 18 ... (1) y = 3x² - 25x + 60 ... (2) Perhatikan kesamaan tempat pada persamaan (1) dan (2) 12 - 6a + 5 = -25 17 - 6a = -25 6a = 17 + 25 a = 42/6 a = 7 3(2 - a)² - 5a + b + 18 = 60 3(-5)² - 35 + b + 18 = 60 75 - 17 + b = 60 b = 60 - 58 b = 2 Maka, nilai a - b = 7 - 2 = 5