Tolong bantu saya

<p>x²+3x-2 memiliki hasil akar-akar sebagai berikut<br>𝞪+𝞫 = -3<br>𝞪.𝞫 = -2<br>1⁄𝞪² + 1⁄𝞫² = 𝞫² + 𝞪² ⁄ &nbsp;(𝞪𝞫)²<br>𝞪²+ 𝞫^2&nbsp; ⁄ &nbsp;(𝞪𝞫)²= (𝞪 + 𝞫)² - 2𝞪𝞫&nbsp;⁄ &nbsp;(𝞪𝞫)²<br>^{&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;}= (-3)² - 2 (-2)&nbsp;⁄ &nbsp;(-2)²</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 9 + 4 / 4<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 13 / 4&nbsp;<br>Maka jawabannya adalah opsi E. 13/4</p>