tolong bantu jawab kakk

<p>Karena sulit menuliskan simbol alpha di keyboard ini, maka akan diganti dengan t.</p><p>Pada saat hmax</p><p>vy = 0</p><p>Maka v1 = vx = v0cost ...(1)</p><p>Lalu,</p><p>vy² = v0y² - 2ghmax</p><p>0 = v0²sin²t - 2ghmax</p><p>2ghmax = v0²sin²t</p><p>hmax = v0²sin²t/(2g) ...(2)</p><p>&nbsp;</p><p>g = 10m/s²</p><p>&nbsp;</p><p>Pada saat ½hmax</p><p>vy² = v0y² - 2g(½hmax)</p><p>Substitusi hmax dari persamaan (2)</p><p>vy² = v0²sin²t - g(v0²sin²t /(2g))</p><p>vy² = v0²sin²t - v0sin²t /2</p><p>vy² = v0²sin²t /2</p><p>vy = v0sint / √2</p><p>vx = v0cost</p><p>Maka,</p><p>v2 = √(vx²+vy²)</p><p>v2 = √(v0²cos²t + v0²sin²t / 2)</p><p>v2 = √(v0²(cos²t + sin²t /2))</p><p>v2 = v0√(cos²t + sin²t / 2)</p><p>&nbsp;</p><p>Diketahui dari soal,</p><p>v1 = √(6/7) v2</p><p>v2/v1 = √(7/6)</p><p>v0√(cos²t + sin²t / 2)/(v0cost) = √(7/6)</p><p>√(cos²t + sin²t/2) / √cos²t = √(7/6)</p><p>√(1 +tan²t/2) = √(7/6)</p><p>1 + tan²t / 2 = 7/6</p><p>tan²t / 2 = 1/6</p><p>tan²t = 1/3</p><p>tant = 1/√3</p><p>Maka, nilai t yg memenuhi adalah 30⁰ agar Tant = 1/√3</p><p>&nbsp;</p><p>Terbukti</p>