sin 135 × cos 315 +sin 30+ tan 240

<p>sin 135° × cos 315° + sin 30° + tan 240°</p><p>&nbsp;</p><p>135° (<i>kuadran I, sin bernilai positif</i>)</p><p>sin (180° - α) = sin α</p><p>180° - 45° = 135°</p><p>sin (180° - 45°) = sin 45° = ½√2.</p><p>&nbsp;</p><p>315° (<i>kuadran IV, cos bernilai positif</i>)</p><p>cos (360° - α) = cos α</p><p>360° - 45° = 315°</p><p>cos (360° - 45°) = cos 45° = ½√2.</p><p>&nbsp;</p><p>sin 30° = ½.</p><p>&nbsp;</p><p>240° (<i>kuadran III, tan bernilai positif</i>)</p><p>tan (180° + α) = tan α</p><p>180° + 60° = 240°</p><p>tan (180° + 60°) = tan 60° = √3.</p><p>&nbsp;</p><p>Maka :</p><p>sin 135° × cos 315° + sin 30° + tan 240°</p><p>½√2 × ½√2 + ½ + √3</p><p>¼ × 2 + ½ + √3</p><p>½ + ½ + √3</p><p>1 + √3.</p><p>&nbsp;</p><p>Jadi, hasilnya adalah 1 + √3.</p><p>&nbsp;</p><p>Semoga membantu.</p>