sebuah kotak berisi 5 bola merah 3 bola putih dan 2 Bola Biru 3 bola diambil secara acak tanpa pengembalian Tentukan ruang sampel percobaan berikut

<p>KOMBINASI</p><p>Total bola dalam kotak : 5 (merah) + 3 (putih) + 2 (biru) = 10 bola</p><p>Jumlah yg diambil : 3 bola secara acak</p><p>Penyelesaian:</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;n (s) = (n/r) = n! / r! (n-r)!</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;n (s) = (10/3) = 10! / 3!(10-3)!</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;n (s) = 10 × 9 × 8 × 7! / (3 × 2 × 1) × 7!</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;n (s) = 10 × 9 × 8 / 3 × 2 × 1</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;n (s) = 720 / 6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;n (s) = 120</p>