Sebuah fungsi kuadrat memiliki persamaan f(x) = x2 + bx + c. Diketahui bahwa grafik fungsi tersebut memotong sumbu x di titik (-2, 0) dan (3, 0). Tentukan nilai b dan c! 1 dan 2 2 dan 1 2 dan 0 3 dan 0 Sebuah tabung memiliki diameter 14 cm dan tinggi 20 cm. Tabung tersebut diisi air hingga penuh. Berapa liter air yang dibutuhkan untuk mengisi tabung tersebut? 3,078 liter 4,124 liter 2,110 liter 3,456 liter Sebuah lingkaran memiliki luas 16π cm². Tentukan keliling lingkaran tersebut! 5π cm 6π cm 7π cm 8π cm Tolong di jawabb yaa🙏🙏

<p>1. f(x) = x² + bx + c</p><p>&nbsp; &nbsp; &nbsp;Melalui (-2,0)</p><p>&nbsp; &nbsp; &nbsp;(-2)² + b(-2) + c = 0</p><p>&nbsp; &nbsp; &nbsp; 4 - 2b + c = 0</p><p>&nbsp; &nbsp; &nbsp;-2b + c = -4 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; (1)</p><p>&nbsp;</p><p>&nbsp; &nbsp; &nbsp;Melalui (3,0)</p><p>&nbsp; &nbsp; &nbsp;3² + 3b + c = 0</p><p>&nbsp; &nbsp; &nbsp;9 + 3b + c = 0</p><p>&nbsp; &nbsp; &nbsp;3b + c = -9 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;(2)</p><p>&nbsp; &nbsp; &nbsp; Eliminasi c dari persamaan (1) dan (2)</p><p>&nbsp; &nbsp; &nbsp; -2b + c = -4&nbsp;</p><p>&nbsp; &nbsp; &nbsp;&nbsp;<u> 3b + c = -9 &nbsp;</u> _</p><p>&nbsp; &nbsp; &nbsp; -5b &nbsp; &nbsp; &nbsp; = 5</p><p>&nbsp; &nbsp; &nbsp; b = -1</p><p>&nbsp;</p><p>&nbsp; &nbsp; &nbsp; Substitusikan b = -1 ke persamaan (1)</p><p>&nbsp; &nbsp; &nbsp; -2b + c = -4</p><p>&nbsp; &nbsp; &nbsp; -2(-1) + c = -4</p><p>&nbsp; &nbsp; &nbsp; 2 + c = -4</p><p>&nbsp; &nbsp; &nbsp; c = -4 - 2</p><p>&nbsp; &nbsp; &nbsp; c = -6</p><p>&nbsp; &nbsp; &nbsp; &nbsp;</p><p>&nbsp; &nbsp; &nbsp; Jadi, nilai b dan c adalah -1 dan -6</p><p>&nbsp;</p><p>2. d = 14 cm</p><p>&nbsp; &nbsp; &nbsp;r = 14/2 = 7 cm</p><p>&nbsp; &nbsp; &nbsp;t = 20 cm</p><p>&nbsp; &nbsp; &nbsp;𝞹 = 22/7</p><p>&nbsp; &nbsp; &nbsp;V = 𝞹 x r² x t</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 22/7 x 7 x 7 x 20</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 3.080 cm³</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 3,080 liter</p><p>&nbsp; &nbsp; &nbsp;Jawaban : 3,078 liter &nbsp;(yang paling mendekati)</p><p>&nbsp;</p><p>3. L = 16𝞹 cm²</p><p>&nbsp; &nbsp; &nbsp;Mancari jari-jari (r)</p><p>&nbsp; &nbsp; &nbsp;L = 𝞹r²</p><p>&nbsp; &nbsp; &nbsp;(16𝞹)/𝞹 = r²</p><p>^{&nbsp; &nbsp; &nbsp; &nbsp;}r²= 16</p><p>&nbsp; &nbsp; &nbsp;r = √16 = 4 cm</p><p>&nbsp;</p><p>&nbsp; &nbsp; &nbsp;K = 2 x 𝞹 x r</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 2 x 𝞹 x 4</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 8𝞹 cm</p><p>&nbsp; &nbsp; &nbsp;Jawaban = &nbsp;8𝞹 cm</p><p>&nbsp;</p>