Sebanyak 25 ml larutan KOH 0,2 M dititrasi dengan larutan HCl 0,1 M dg variasi penambahan volume dalam (ml) 0,5,10,15,20,25,30,35. Buatkan grafiknya!

<p>Diketahui:<br>Volume KOH = 25 mL<br>Konsentrasi KOH = 0,2 M<br>Konsentrasi HCl = 0,1 M<br>Mol KOH mula-mula = 0,025 × 0,2 = 0,005 mol.<br>&nbsp;</p><p>Titik ekuivalen terjadi saat:</p><p>V HCl = 0,005/0,1 = 0,05 L = 50 mL</p><p>Karena volume HCl yang ditambahkan hanya sampai 35 mL, larutan masih bersifat basa.</p><p><br>Hasil perhitungan pH:<br>Volume HCl (mL). &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;pH<br>0. &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 13,30<br>5. &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 13,22<br>10. &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 13,12<br>15. &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 13,00<br>20. &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 12,85<br>25. &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 12,70<br>30. &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 12,48<br>35. &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 12,18<br><br>Grafik pH terhadap volume HCl:</p><p><br>Kurva Titrasi KOH 0,2 M (25 mL) dengan HCl 0,1 M<br>Perubahan pH terhadap penambahan volume HCl hingga 35 mL.<br>&nbsp;</p><p>&nbsp;</p><p><br>Grafik menunjukkan bahwa pH menurun secara bertahap karena HCl menetralkan KOH. Penurunan tajam belum terlihat karena titik ekuivalen baru tercapai pada 50 mL HCl</p>