Hitunglah Ksp senyawa Ni(OH)2 (Mr = 93) dengan nilai s = 2,325 x 10^-4 g/L !

<p>Jawaban yang benar adalah 6,25 x 10^-17</p><p>&nbsp;</p><p>Pembahasan</p><p>Kelarutan (solubility = s) adalah konsentrasi maksimum zat terlarut dalam suatu larutan.&nbsp;</p><p>Larutan yang mengandung zar terlarut dengan konsentrasi maksimum disebut larutan jenuh.</p><p>Pada larutan jenuh, zat terlarut berada dalam kesetimbangan antara fasa padat dengan ion-ionnya, sehingga terdapat tetapan kesetimbangan yang disebut dengan tetapan hasil kali kelarutan (Ksp)</p><p>&nbsp;</p><p>Ni(OH)2 &nbsp; ⇄&nbsp; &nbsp;Ni²⁺ &nbsp; + &nbsp; 2OH^-</p><p>s &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;s &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 2s</p><p>&nbsp;</p><p>diketahui s = 2,325 x 10^-4 g/L</p><p>artinya massa Ni(OH)2 = 2,325 x 10^-4 g</p><p>V = 1 L</p><p>&nbsp;</p><p>mol Ni(OH)2 = massa / Mr</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= &nbsp;2,325 x 10^-4 g / 93 gr/mol</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 0,025 x 10^-4 mol</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 2,5 x 10^-6 mol</p><p>&nbsp;</p><p>s Ni(OH)2 = mol / V</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 2,5 x 10^-6 mol / 1L</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 2,5 x 10^-6 mol/L</p><p>&nbsp;</p><p>Ksp = [Ni^2+] x [OH^-]^2</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= s x (2s)^2</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 4s^3</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 4 x (2,5 x 10^-6)^3</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 4 x (15,625 x 10^-18)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 62,5 x 10^-18</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 6,25 x 10^-17</p><p>&nbsp;</p><p>Maka Ksp Ni(OH)2 adalah 6,25 x 10^-17</p>