Diketahui matriks A=[(3 5)(4 7)] dan matriks B=[(1 -2)(-1 -5)]. Jika C=A+B, invers matriks C adalah ....

Hai Meta, kaka bantu jawab yaa Jawaban:C⁻¹= [(-2 3)(3 -4)] Konsep: A=[(a1 a2)(a3 a4)] B=[(b1 b2)(b3 b4)] A + B = [(a1+b1 a2+b2)(a3+b3 a4+b4)] Invers A = 1/(a1·a4 - a2·a3) [(a4 -a2)(-a3 a1)] Pembasan: A=[(3 5)(4 7)] B=[(1 -2)(-1 -5)] C = A+B C = [(3 5)(4 7)] + [(1 -2)(-1 -5)] C = [(3+1 5-2)(4-1 7-5)] C = [(4 3)(3 2)] Jadi matriks C adalah [(4 3)(3 2)] Mencari invers C C⁻¹= 1/(4 · 2 - 3·3) [(2 -3)(-3 4)] C⁻¹= 1/(8 - 9) [(2 -3)(-3 4)] C⁻¹= 1/(-1) [(2 -3)(-3 4)] C⁻¹= [(-2 3)(3 -4)] JAdi invers matriks C adalah C⁻¹= [(-2 3)(3 -4)]