Naval H

10 April 2024 13:17

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Naval H

10 April 2024 13:17

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Tjendana T

Community

11 April 2024 04:35

Jawaban terverifikasi

<p>Jawaban &nbsp;<strong>B. 12 watt</strong></p><p>&nbsp;</p><p><strong>Pembahasan&nbsp;</strong></p><p>1/Rp = 1/R2 + 1/R3</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 1/3 + 1/6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 3/6</p><p>&lt;=&gt; Rp = 2 Ω</p><p>&nbsp;</p><p>Rs = R1 + Rp</p><p>&nbsp; &nbsp; &nbsp; = 1 + 2</p><p>&nbsp; &nbsp; &nbsp; = 3 Ω</p><p>&nbsp;</p><p>P = V²/R</p><p>&nbsp; &nbsp;= 6²/3</p><p>&nbsp; &nbsp;= 12 W</p>

Jawaban  B. 12 watt

 

Pembahasan 

1/Rp = 1/R2 + 1/R3

          = 1/3 + 1/6

         = 3/6

<=> Rp = 2 Ω

 

Rs = R1 + Rp

      = 1 + 2

      = 3 Ω

 

P = V²/R

   = 6²/3

   = 12 W


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Sumber W

Community

11 April 2024 14:30

Jawaban terverifikasi

<p>Jawaban yang tepat adalah B. 12 watt</p><p>&nbsp;</p><p>Pembahasan :</p><p>Mencari hambatan pengganti Paralel</p><p>1/R<sub>p</sub> = 1/R<sub>2</sub> + 1/R<sub>3</sub></p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 1/3 + 1/6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 2/6 + 1/6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 3/6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 1/2</p><p>&nbsp; R<sub>p</sub> = 2 𝞨</p><p>&nbsp;</p><p>Menentukan Hambatan Total</p><p>R<sub>total</sub> = R<sub>1</sub> + R<sub>p</sub></p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 1 + 2</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 3 𝞨</p><p>Menentukan daya Listrik (P)</p><p>V = 6 volt</p><p>P = V<sup>2</sup>/R<sub>total</sub></p><p>&nbsp; &nbsp; = 6<sup>2</sup>/3</p><p>&nbsp; &nbsp; = 36/3</p><p>&nbsp; &nbsp; = 12 watt</p>

Jawaban yang tepat adalah B. 12 watt

 

Pembahasan :

Mencari hambatan pengganti Paralel

1/Rp = 1/R2 + 1/R3

          = 1/3 + 1/6

          = 2/6 + 1/6

          = 3/6

          = 1/2

  Rp = 2 𝞨

 

Menentukan Hambatan Total

Rtotal = R1 + Rp

              = 1 + 2

              = 3 𝞨

Menentukan daya Listrik (P)

V = 6 volt

P = V2/Rtotal

    = 62/3

    = 36/3

    = 12 watt


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