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<p>Jawaban :</p><p>Hitung pOH = 14-pH</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 14 - 9</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 5</p><p>[OH-] = 10^-pOH = 10^ -5 M</p><p>Kb = Kw/Ka</p><p>&nbsp; &nbsp; &nbsp; = (1,0 × 10^-14) / (10^5)&nbsp;</p><p>&nbsp; &nbsp; &nbsp; = 1,0 × 10^-9</p><p>Misal, konsentrasi awal CH3COOHNa adalah [C]</p><p>[CH3COOH] = 10^-5 M (dari stokiometri dengan OH)</p><p>kesetimbangan = C - 10^-5</p><p>Subtitusikan :</p><p>Kb = ( [CH3COOH][OH-]) / [CH3COO-]</p><p>&nbsp;1,0 × 10^-9 = (10^-5 * 10^-5) / (C - 10^-5)</p><p>1,0 × 10^-9 = (10^-10) / ( C - 10^-5)</p><p>Susun ulang utk mencari &nbsp;C- 10^-5</p><p>C - 10^-5 = 10^-10 / (1,0×10^-9)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 10^-1</p><p>C - 0,00001 = 0,1</p><p>C = 0,1 + 0,00001</p><p>C = 0,10001 M</p><p>Jadi, konsentrasi awal CH3COONa dan( CH3COO-) adalah sekitar 0,1 M</p><p>% hidrolisis = (10^-5 / 0,10001) * 100%</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 0,009999%</p><p>Jadi, Presentase hidrolisis CH3COONa adalah sekitar 0,01% (di bulatkan)</p><p>&nbsp; &nbsp;</p>