[1/(⁶log24)] + [1/(⁸log24)] + [1/(¹²log24)] = .... A. −1 B. 0 C. 1 D. 2 E. 3

<p>Jawaban yang benar adalah C.</p><p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</p><p>Perhatikan konsep berikut.</p><p>1/^alogb = ^bloga</p><p>^alogb + ^alogc = ^alog(b x c)</p><p>^alogb^m = m x ^alogb</p><p>^aloga = 1</p><p>&nbsp;</p><p>Sehingga:</p><p>&nbsp;[1/(⁶log24)] + [1/(⁸log24)] + [1/(¹²log24)]</p><p>= &nbsp;²⁴log6 + ²⁴log8 + ²⁴log12</p><p>= &nbsp;²⁴log(6 x 8 x 12)</p><p>= &nbsp;²⁴log576</p><p>= ²⁴log24²</p><p>= 2 x ²⁴log24</p><p>= 2 x 1</p><p>= 2</p><p>&nbsp;</p><p>Oleh karena itu, jawabannya adalah C.</p><p>Semoga membantu ya, semangat belajar :)</p>