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Pertanyaan

Vitamin C memiliki nama kimia asam askorbat. Strukturnya dapat melepas dua undefined

begin mathsize 12px style H subscript 2 C subscript 6 H subscript 6 O subscript 6 open parentheses aq close parentheses equilibrium H to the power of plus sign open parentheses aq close parentheses and H C subscript 6 H subscript 6 O subscript 6 to the power of minus sign open parentheses aq close parentheses space space Ka subscript 1 equals 7 comma 9 cross times 10 to the power of negative sign 5 end exponent H C subscript 6 H subscript 6 O subscript 6 to the power of minus sign open parentheses aq close parentheses equilibrium H to the power of plus sign open parentheses aq close parentheses and C subscript 6 H subscript 6 O subscript 6 to the power of negative sign 2 end exponent open parentheses aq close parentheses space space Ka subscript 2 equals 1 comma 6 cross times 10 to the power of negative sign 12 end exponent end style   

Jika produk minuman botol vitamin C 1000 mg memiliki volume 500 mL, maka jumlah mol undefined yang dihasilkan dari ioniasi vitamin C (Mr =  176) dalam larutan tersebut adalah ….

  1. begin mathsize 12px style 6 comma 70 cross times 10 to the power of negative sign 3 end exponent end style   

  2. begin mathsize 12px style 5 comma 68 cross times 10 to the power of negative sign 3 end exponent end style  

  3. begin mathsize 12px style 4 comma 54 cross times 10 to the power of negative sign 3 end exponent end style  

  4. begin mathsize 12px style 6 comma 70 cross times 10 to the power of negative sign 4 end exponent end style   

  5. begin mathsize 12px style 9 comma 47 cross times 10 to the power of negative sign 4 end exponent end style   

A. Chandra

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

Nilai Ka pada ionisasi tahap pertama memiliki orde begin mathsize 12px style 10 to the power of negative sign 5 end exponent end style sedangkan tahap kedua begin mathsize 12px style 10 to the power of negative sign 12 end exponent end style. Selisih keduanya sangat jauh sehingga dipastikan undefined yang diperoleh dari tahap kedua terlalu kecil untuk dijumlahkan. Jadi, hanya persamaan tahap pertama yang digunakan.  

begin mathsize 12px style mol subscript VitC equals fraction numerator massa open parentheses g close parentheses over denominator Mr end fraction equals fraction numerator 1 space g over denominator 176 g forward slash mol end fraction equals 5 comma 68 cross times 10 to the power of negative sign 3 end exponent space mol open square brackets H to the power of plus sign close square brackets equals square root of Ka subscript 1 cross times M end root end style    

Volume larutan 500 mL = 0,5 L sehingga:

begin mathsize 12px style open square brackets H to the power of plus sign close square brackets equals square root of 7 comma 9 cross times 10 to the power of negative sign 5 end exponent cross times fraction numerator 5 comma 68 cross times 10 to the power of negative sign 3 end exponent over denominator 0 comma 5 end fraction end root open square brackets H to the power of plus sign close square brackets equals square root of 89 comma 74 cross times 10 to the power of negative sign 8 end exponent end root open square brackets H to the power of plus sign close square brackets equals 9 comma 47 cross times 10 to the power of negative sign 4 end exponent end style     

 

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