Unsur nitrogen dan oksigen bereaksi, dan dapat membentuk lebih dari satu macam senyawa. Tentukan besarnya persentase unsur nitrogen dan oksigen dalam senyawa !

Pertanyaan

Unsur nitrogen dan oksigen bereaksi, dan dapat membentuk lebih dari satu macam senyawa. Tentukan besarnya persentase unsur nitrogen dan oksigen dalam senyawa $N O comma space N O subscript 2 comma space N subscript 2 O comma space N subscript 2 O subscript 3 comma space dan space N subscript 2 O subscript 5 space left parenthesis Ar space N equals 14 space dan space O equals 16 right parenthesis$ !

Pembahasan Soal:

Untuk zat berupa senyawa, komposisinya secara teoritis dapat dinyatakan dalam persen massa unsur dalam senyawa.

$percent sign unsur space equals space fraction numerator angka space indeks cross times Ar space unsur over denominator Mr space senyawa end fraction cross times 100 percent sign$

Menghitung kadar unsur dalam senyawa:

Persen unsur nitrogen dan oksigen dalam senyawa $N O$ .

$table attributes columnalign right center left columnspacing 0px end attributes row cell Ar space N end cell equals 14 row cell Ar space O end cell equals 16 row cell Mr space N O end cell equals cell Ar space N and Ar space O end cell row blank equals cell 14 plus 16 end cell row blank equals 30 row blank blank blank row cell percent sign space N end cell equals cell space fraction numerator angka space indeks space N cross times Ar space N over denominator Mr space N O end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 1 cross times 14 over denominator 30 end fraction cross times 100 percent sign end cell row blank equals cell 46 comma 7 percent sign end cell row blank blank blank row cell percent sign space O end cell equals cell space fraction numerator angka space indeks space O cross times Ar space O over denominator Mr space N O end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 1 cross times 16 over denominator 30 end fraction cross times 100 percent sign end cell row blank equals cell 53 comma 3 percent sign end cell end table$
Persen unsur nitrogen dan oksigen dalam senyawa $N O subscript 2$ .

$table attributes columnalign right center left columnspacing 0px end attributes row cell Ar space N end cell equals 14 row cell Ar space O end cell equals 16 row cell Mr space N O subscript 2 end cell equals cell Ar space N plus 2 left parenthesis Ar space O right parenthesis end cell row blank equals cell 14 plus 2 left parenthesis 16 right parenthesis end cell row blank equals 46 row blank blank blank row cell percent sign space N end cell equals cell space fraction numerator angka space indeks space N cross times Ar space N over denominator Mr space N O subscript 2 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 1 cross times 14 over denominator 46 end fraction cross times 100 percent sign end cell row blank equals cell 30 comma 43 percent sign end cell row blank blank blank row cell percent sign space O end cell equals cell space fraction numerator angka space indeks space O cross times Ar space O over denominator Mr space N O subscript 2 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 2 cross times 16 over denominator 46 end fraction cross times 100 percent sign end cell row blank equals cell 69 comma 57 percent sign end cell end table$
Persen unsur nitrogen dan oksigen dalam senyawa $N subscript 2 O$ .

$table attributes columnalign right center left columnspacing 0px end attributes row cell Ar space N end cell equals 14 row cell Ar space O end cell equals 16 row cell Mr space N subscript 2 O end cell equals cell 2 left parenthesis Ar space N right parenthesis plus Ar space O end cell row blank equals cell 2 left parenthesis 14 right parenthesis plus 16 end cell row blank equals 44 row blank blank blank row cell percent sign space N end cell equals cell space fraction numerator angka space indeks space N cross times Ar space N over denominator Mr space N subscript 2 O end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 2 cross times 14 over denominator 44 end fraction cross times 100 percent sign end cell row blank equals cell 63 comma 63 percent sign end cell row blank blank blank row cell percent sign space O end cell equals cell space fraction numerator angka space indeks space O cross times Ar space O over denominator Mr space N subscript 2 O end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 1 cross times 16 over denominator 44 end fraction cross times 100 percent sign end cell row blank equals cell 36 comma 36 percent sign end cell end table$
Persen unsur nitrogen dan oksigen dalam senyawa $N subscript 2 O subscript 3$ .

$table attributes columnalign right center left columnspacing 0px end attributes row cell Ar space N end cell equals 14 row cell Ar space O end cell equals 16 row cell Mr space N subscript 2 O subscript 3 end cell equals cell 2 left parenthesis Ar space N right parenthesis plus 3 left parenthesis Ar space O right parenthesis end cell row blank equals cell 2 left parenthesis 14 right parenthesis plus 3 left parenthesis 16 right parenthesis end cell row blank equals 76 row blank blank blank row cell percent sign space N end cell equals cell space fraction numerator angka space indeks space N cross times Ar space N over denominator Mr space space N subscript 2 O subscript 3 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 2 cross times 14 over denominator 76 end fraction cross times 100 percent sign end cell row blank equals cell 36 comma 84 percent sign end cell row blank blank blank row cell percent sign space O end cell equals cell space fraction numerator angka space indeks space O cross times Ar space O over denominator Mr space space N blank subscript 2 O blank subscript 3 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 3 cross times 16 over denominator 76 end fraction cross times 100 percent sign end cell row blank equals cell 61 comma 16 percent sign end cell end table$
Persen unsur nitrogen dan oksigen dalam senyawa $N subscript 2 O subscript 5$ .

$table attributes columnalign right center left columnspacing 0px end attributes row cell Ar space N end cell equals 14 row cell Ar space O end cell equals 16 row cell Mr space N subscript 2 O subscript 5 end cell equals cell 2 left parenthesis Ar space N right parenthesis plus 5 left parenthesis Ar space O right parenthesis end cell row blank equals cell 2 left parenthesis 14 right parenthesis plus 5 left parenthesis 16 right parenthesis end cell row blank equals 108 row blank blank blank row cell percent sign space N end cell equals cell space fraction numerator angka space indeks space N cross times Ar space N over denominator Mr space space N subscript 2 O subscript 5 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 2 cross times 14 over denominator 108 end fraction cross times 100 percent sign end cell row blank equals cell 25 comma 93 percent sign end cell row blank blank blank row cell percent sign space O end cell equals cell space fraction numerator angka space indeks space O cross times Ar space O over denominator Mr space space N subscript 2 O subscript 5 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 5 cross times 16 over denominator 108 end fraction cross times 100 percent sign end cell row blank equals cell 74 comma 07 percent sign end cell end table$

Jadi, persen unsur nitrogen dan oksigen dalam senyawa $N O$ adalah $46 comma 7 percent sign space dan space 53 comma 3 percent sign$ , persen unsur nitrogen dan oksigen dalam senyawa adalah $N O subscript 2$ adalah $30 comma 43 percent sign space dan space 69 comma 67 percent sign$ , persen unsur nitrogen dan oksigen dalam senyawa $N subscript 2 O$ adalah $63 comma 63 percent sign space dan space 36 comma 36 percent sign$ , persen unsur nitrogen dan oksigen dalam senyawa $N subscript 2 O subscript 3$ adalah $36 comma 84 percent sign space dan space 61 comma 16 percent sign$ , dan persen unsur nitrogen dan oksigen dalam senyawa $N subscript 2 O subscript 5$ adalah $25 comma 93 percent sign space dan space 74 comma 07 percent sign$ .

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 04 Juni 2021

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