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UAN 2002 (soal tipe penalaran) Energy foton sinar gamma  ( 1 eV = ) dan jika tetapan planck = , maka panjang gelombang sinar gamma adalah ....

Pertanyaan

UAN 2002 (soal tipe penalaran)
Energy foton sinar gamma begin mathsize 14px style 10 to the power of 8 space eV end style ( 1 eV = begin mathsize 14px style 1 comma 6 cross times 10 to the power of negative 19 end exponent space joule end style) dan jika tetapan planck = begin mathsize 14px style 6 comma 6 cross times 10 to the power of negative 34 end exponent space straight J. straight s end style, maka panjang gelombang sinar gamma adalah ....

  1. begin mathsize 14px style 4 comma 125 cross times 10 to the power of negative 15 end exponent space straight A end style 

  2. begin mathsize 14px style 1 comma 2375 cross times 10 to the power of negative 14 end exponent space straight A end style 

  3. begin mathsize 14px style 7 comma 27 cross times 10 to the power of negative 6 end exponent space straight A end style 

  4. begin mathsize 14px style 4 comma 125 cross times 10 to the power of negative 5 end exponent space straight A end style 

  5. begin mathsize 14px style 1 comma 2375 cross times 10 to the power of negative 4 end exponent space straight A end style 

Pembahasan Soal:

begin mathsize 14px style E equals 10 to the power of 8 space eV 1 space eV equals 1 comma 6 cross times 10 to the power of negative 19 end exponent space joule h equals 6 comma 6 cross times 10 to the power of negative 34 end exponent space straight J. straight s end style 

Ditanyakan: panjang gelombang?
Jawab:

begin mathsize 14px style E equals h c over lambda lambda equals fraction numerator h c over denominator E end fraction lambda equals fraction numerator open parentheses 6 comma 6 cross times 10 to the power of negative 34 end exponent close parentheses open parentheses 3 cross times 10 to the power of 8 close parentheses over denominator open parentheses 10 to the power of 8 cross times 1 comma 6 cross times 10 to the power of negative 19 end exponent close parentheses end fraction lambda equals 12 comma 375 cross times 10 to the power of negative 15 end exponent space straight m lambda equals 1 comma 2375 cross times 10 to the power of negative 4 end exponent space straight Å end style 

Jadi, jawaban yang tepat adalah E. begin mathsize 14px style bold 1 bold comma bold 2375 bold cross times bold 10 to the power of bold minus bold 4 end exponent end style Å. 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 14 Maret 2021

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