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Tiga buah muatan A, B, dan C membentuk segitiga dengan sudut siku – siku di A seperti gambar berikut. Jika besar muatan Q A = + 10 μC, Q B = -4 μC, dan Q C = - 4 μC, serta k adalah konstanta coulomb, masing – masing muatan terpisah pada jarak 2 cm, maka resultan gaya pada muatan A adalah ….

Tiga buah muatan A, B, dan C membentuk segitiga dengan sudut siku – siku di A seperti gambar berikut.

Jika besar muatan QA = + 10 μC, QB = -4 μC, dan QC = - 4 μC, serta k adalah konstanta coulomb, masing – masing muatan terpisah pada jarak 2 cm, maka resultan gaya pada muatan A adalah ….

  1. k square root of 2 space x space 10 to the power of negative 7 end exponent space N

  2. k square root of 3 space x space 10 to the power of negative 7 end exponent space N

  3. k square root of 2 space x space 10 to the power of negative 8 end exponent space N

  4. k square root of 3 space x space 10 to the power of negative 8 end exponent space N

  5. k square root of 2 space x space 10 to the power of negative 6 end exponent space N

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A. Aulia

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Cari space besar space gaya space straight F subscript AB space dan space straight F subscript BC space colon

F subscript A B end subscript equals fraction numerator k Q subscript A Q subscript B over denominator r subscript A B end subscript superscript 2 end fraction equals fraction numerator k open parentheses 10 x 10 to the power of negative 6 end exponent close parentheses open parentheses 4 x 10 to the power of negative 6 end exponent close parentheses over denominator open parentheses 2 x 10 to the power of negative 2 end exponent close parentheses squared end fraction equals fraction numerator 40 space x space 10 to the power of negative 12 end exponent k over denominator 4 space x space 10 to the power of negative 4 end exponent end fraction F subscript A B end subscript equals 10 space x space 10 to the power of negative 8 end exponent k equals 1 space x space 10 to the power of negative 7 end exponent k space N F subscript A C end subscript equals fraction numerator k Q subscript A Q subscript C over denominator r subscript A C end subscript superscript 2 end fraction equals fraction numerator k left parenthesis 10 x 10 to the power of negative 6 end exponent right parenthesis left parenthesis 4 x 10 to the power of negative 6 end exponent right parenthesis over denominator open parentheses 2 x 10 to the power of negative 2 end exponent close parentheses squared end fraction equals fraction numerator 40 space x space 10 to the power of negative 12 end exponent k over denominator 4 space x space 10 to the power of negative 4 end exponent end fraction F subscript A C end subscript equals 10 space x space 10 to the power of negative 8 end exponent space k equals 1 space x space 10 to the power of negative 7 end exponent k space N

Misalkan space 1 k space cross times space 10 to the power of negative 7 end exponent space straight N equals straight X Maka space colon

F subscript A equals square root of open parentheses F subscript A B end subscript close parentheses squared plus open parentheses F subscript A C end subscript close parentheses squared end root F subscript A equals square root of X squared plus X squared end root F subscript A equals square root of 2 X squared end root F subscript A equals X square root of 2 F subscript A equals k square root of 2 space x space 10 to the power of negative 7 end exponent space N

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Tiga buah muatan diletakkan sedemikian sehingga posisinya membentuk segitiga sama sisi seperti gambar berikut. Masing-masing muatan terpisah pada jarak 2 cm. Jika Q A = +10 μC, Q B = -5 μC, dan ...

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