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Tentukan pH larutan berikut 100 ml Amonium Hidroksida 0,4 M

Pertanyaan

Tentukan pH larutan berikut

100 ml Amonium Hidroksida 0,4 M begin mathsize 14px style left parenthesis K subscript italic a italic space equals space 1 space x space 10 to the power of negative sign 5 end exponent right parenthesis end style  space space 

  1. ... space space 

  2. ... space space 

Pembahasan Soal:

Amonium hidroksida (begin mathsize 14px style N H subscript 4 O H end style) merupakan basa lemah, pH amonium hidroksida dihitung menggunakan persamaan:


begin mathsize 14px style open square brackets O H to the power of minus sign close square brackets equals square root of K subscript b cross times M subscript N H subscript 4 O H end subscript end root open square brackets O H to the power of minus sign close square brackets equals square root of 1 cross times 10 to the power of negative sign 5 end exponent cross times 0 comma 4 space M end root open square brackets O H to the power of minus sign close square brackets equals square root of 4 cross times 10 to the power of negative sign 6 end exponent space M end root open square brackets O H to the power of minus sign close square brackets equals 2 cross times 10 to the power of negative sign 3 end exponent thin space M   pOH equals minus sign log space open square brackets O H to the power of minus sign close square brackets pOH equals minus sign log space open parentheses 2 cross times 10 to the power of negative sign 3 end exponent close parentheses pOH equals 3 minus sign log space 2   pH equals 14 minus sign pOH pH equals 14 minus sign open parentheses 3 minus sign log space 2 close parentheses pH equals 11 plus log space 2 end style 


Jadi, pH larutan amonium hidroksida 0,4 M adalah 11+log 2.undefined

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 05 Maret 2021

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