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Pertanyaan

Tentukan pH dari larutan garam fluorida berikut jika Ka HF = 7,2 x10-4 (Larutan KF 0,72 M) ...space 

A. Tri

Master Teacher

Mahasiswa/Alumni Universitas Pertamina

Jawaban terverifikasi

Jawaban

dapat disimpulkan jawaban yang tepat adalah 8 + log 3,2.space

Pembahasan

Rumus pH garam basa yaitu:
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell 14 minus sign pOH end cell row pOH equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of Kw over Ka cross times open square brackets G close square brackets end root end cell row blank equals cell square root of fraction numerator 10 to the power of negative sign 14 end exponent over denominator 7 comma 2.10 to the power of negative sign 4 end exponent end fraction cross times 0 comma 72 end root end cell row blank equals cell square root of 1.10 to the power of negative sign 11 end exponent end root end cell row blank equals cell 3 comma 2 cross times 10 to the power of negative sign 6 end exponent end cell row pOH equals cell negative sign log space 3 comma 2 cross times 10 to the power of negative sign 6 end exponent end cell row blank equals cell 6 minus sign log space 3 comma 2 end cell row blank blank blank row pH equals cell 14 minus sign left parenthesis 6 minus sign log space 3 comma 2 right parenthesis end cell row blank equals cell 8 plus log space 3 comma 2 end cell end table end style 
 

Jadi, dapat disimpulkan jawaban yang tepat adalah 8 + log 3,2.space

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