Iklan

Iklan

Pertanyaan

Tentukan persentase kadar masing-masing unsur dalam senyawaberikut. b. Na 3 ​ PO 4 ​

Tentukan persentase kadar masing-masing unsur dalam senyawa berikut.

b.  

Iklan

A. Chandra

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Jawaban

% Na, % P, dan % O dalam senyawa berturut-turut adalah 42,07%, 18,9%, dan 39,02%.

% Na, % P, dan % O dalam senyawa berturut-turut adalah 42,07%, 18,9%, dan 39,02%.

Iklan

Pembahasan

Diketahui Na = 23, P = 31, O = 16, sehingga nilai : Menentukan persentase kadar masing-masing unsur: Jadi % Na, % P, dan % O dalam senyawa berturut-turut adalah 42,07%, 18,9%, dan 39,02%.

Diketahui italic A subscript r Na = 23, P = 31, O = 16, sehingga nilai italic M subscript r space Na subscript 3 P O subscript 4:

table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r space Na subscript 3 P O subscript 4 end cell equals cell left parenthesis 3 cross times italic A subscript r space Na right parenthesis plus left parenthesis 1 cross times italic A subscript r space P right parenthesis plus left parenthesis 4 cross times italic A subscript r space O right parenthesis end cell row blank equals cell left parenthesis 3 cross times 23 right parenthesis plus left parenthesis 1 cross times 31 right parenthesis plus left parenthesis 4 cross times 16 right parenthesis end cell row blank equals cell 69 plus 31 plus 64 end cell row blank equals cell 164 space g space mol to the power of negative sign 1 end exponent end cell end table 

Menentukan persentase kadar masing-masing unsur:

table attributes columnalign right center left columnspacing 0px end attributes row cell percent sign Na end cell equals cell fraction numerator 3 cross times italic A subscript r space Na over denominator italic M subscript r space Na subscript 3 P O subscript 4 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 3 cross times 23 over denominator 164 end fraction cross times 100 percent sign end cell row blank equals cell 69 over 164 cross times 100 percent sign end cell row blank equals cell 42 comma 07 percent sign end cell end table  

  table attributes columnalign right center left columnspacing 0px end attributes row cell percent sign P end cell equals cell fraction numerator 1 cross times italic A subscript r space P over denominator italic M subscript r space Na subscript 3 P O subscript 4 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 1 cross times 31 over denominator 164 end fraction cross times 100 percent sign end cell row blank equals cell 31 over 164 cross times 100 percent sign end cell row blank equals cell 18 comma 9 percent sign end cell end table 

table attributes columnalign right center left columnspacing 0px end attributes row cell percent sign O end cell equals cell fraction numerator 4 cross times italic A subscript r space O over denominator italic M subscript r space Na subscript 3 P O subscript 4 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 4 cross times 16 over denominator 164 end fraction cross times 100 percent sign end cell row blank equals cell 64 over 164 cross times 100 percent sign end cell row blank equals cell 39 comma 02 percent sign end cell end table 

Jadi % Na, % P, dan % O dalam senyawa berturut-turut adalah 42,07%, 18,9%, dan 39,02%.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

4

Iklan

Iklan

Pertanyaan serupa

Tentukan persentase kadar masing-masing unsur dalam senyawaberikut. c. K 4 ​ [ Fe ( CN ) 6 ​ ]

24

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia