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Tentukan nilai pH dari larutan berikut! a. 0,01 M NaOH b.0,001 M H 2 SO 4 c. 0,001 M CH 3 COOH, K a = 10 -6

Tentukan nilai pH dari larutan berikut!space 

a. 0,01 M NaOH
b. 0,001 M H2SO4 
c. 0,001 M CH3COOH, Ka = 10-6
 

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A. Acfreelance

Master Teacher

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Jawaban

maka pH larutan NaOH adalah12 , H 2 SO 4 adalah 3 - log 2, dan CH 3 COOH adalah 4,5.

maka pH larutan NaOH adalah 12 , H2SO4 adalah 3 - log 2, dan CH3COOH adalah 4,5.

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Pembahasan

Dengan demikian, maka pH larutan NaOH adalah12 , H 2 SO 4 adalah 3 - log 2, dan CH 3 COOH adalah 4,5.

a point space open square brackets O H to the power of minus sign close square brackets equals open square brackets Na O H close square brackets equals 0 comma 01 space M pOH equals minus sign log open square brackets O H to the power of minus sign close square brackets pOH equals minus sign log open parentheses 0 comma 01 close parentheses pOH equals 2 pH equals 12  b point space open square brackets H to the power of plus sign close square brackets equals 2 cross times open square brackets H subscript 2 S O subscript 4 close square brackets open square brackets H to the power of plus sign close square brackets equals 2 cross times 0 comma 001 equals 0 comma 002 space M pH equals minus sign log open square brackets H to the power of plus sign close square brackets pH equals minus sign log open parentheses 0 comma 002 close parentheses pH equals 3 minus sign log space 2  c point space open square brackets H to the power of plus sign close square brackets equals square root of K subscript a cross times open square brackets C H subscript 3 C O O H close square brackets end root open square brackets H to the power of plus sign close square brackets equals square root of 10 to the power of negative sign 6 end exponent cross times 0 comma 001 end root open square brackets H to the power of plus sign close square brackets equals 10 to the power of negative sign 4 comma 5 end exponent pH equals minus sign log open square brackets H to the power of plus sign close square brackets pH equals minus sign log open parentheses 10 to the power of negative sign 4 comma 5 end exponent close parentheses pH equals 4 comma 5

Dengan demikian, maka pH larutan NaOH adalah 12 , H2SO4 adalah 3 - log 2, dan CH3COOH adalah 4,5.

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