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Tentukan nilai limit berikut!

 begin mathsize 14px style limit as x rightwards arrow 1 half of fraction numerator square root of 6 x end root minus square root of 3 over denominator 2 square root of 2 x end root minus 2 end fraction end style          

  1. .... 

  2. .... 

L. Rante

Master Teacher

Mahasiswa/Alumni Universitas Negeri Makassar

Jawaban terverifikasi

Pembahasan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 1 half of fraction numerator square root of 6 x end root minus square root of 3 over denominator 2 square root of 2 x end root minus 2 end fraction end cell equals cell limit as x rightwards arrow 1 half of fraction numerator square root of 3 open parentheses square root of 2 x end root minus 1 close parentheses over denominator 2 open parentheses square root of 2 x end root minus 1 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 1 half of fraction numerator square root of 3 over denominator 2 end fraction end cell row blank equals cell fraction numerator square root of 3 over denominator 2 end fraction end cell end table end style 

35

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Tentukan nilai limit berikut!  x→4lim​x​−212+x−x2​

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