Pertanyaan

Tentukan nilai dari: b. ( 8 − 5 ⋅ 4 ( − 3 ) 2 ⋅ 6 2 1 ) ÷ ( − 5 2 7 ) − 1

Tentukan nilai dari:

b. $(\frac{- 5}{8} \cdot \frac{( - 3 ) ^{2}}{4} \cdot \frac{1}{6 ^{2}}) \div (- \frac{2 ^{7}}{5})^{- 1}$

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

nilai dari adalah .

nilai dari $open parentheses fraction numerator negative 5 over denominator 8 end fraction times open parentheses negative 3 close parentheses squared over 4 times 1 over 6 squared close parentheses divided by open parentheses negative 2 to the power of 7 over 5 close parentheses to the power of negative 1 end exponent$ adalah

Pembahasan

Ingatlah sifat-sifat bilangan berpangkat sebagai berikut. Berdasarkan sifat-sifat di atas, maka: Dengan demikian, nilai dari adalah .

Ingatlah sifat-sifat bilangan berpangkat sebagai berikut.

left parenthesis straight i right parenthesis space space open parentheses a cross times b close parentheses to the power of m equals a to the power of m cross times b to the power of m left parenthesis ii right parenthesis space space a to the power of m cross times a to the power of n equals a to the power of m plus n end exponent

Berdasarkan sifat-sifat di atas, maka:

$table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open parentheses fraction numerator negative 5 over denominator 8 end fraction times open parentheses negative 3 close parentheses squared over 4 times 1 over 6 squared close parentheses divided by open parentheses negative 2 to the power of 7 over 5 close parentheses to the power of negative 1 end exponent end cell row blank equals cell open parentheses fraction numerator negative 5 over denominator 2 cubed end fraction times open parentheses negative 3 close parentheses squared over 2 squared times 1 over open parentheses 2 times 3 close parentheses squared close parentheses divided by open parentheses negative 5 over 2 to the power of 7 close parentheses end cell row blank equals cell fraction numerator open parentheses fraction numerator negative 5 over denominator 2 cubed end fraction times fraction numerator up diagonal strike open parentheses negative 3 close parentheses squared end strike over denominator 2 squared end fraction times begin display style 1 over 2 squared end style times begin display style fraction numerator 1 over denominator up diagonal strike 3 squared end strike end fraction end style close parentheses over denominator negative begin display style 5 over 2 to the power of 7 end style end fraction end cell row blank equals cell fraction numerator negative 5 over denominator 2 cubed cross times 2 squared cross times 2 squared end fraction cross times open parentheses negative 2 to the power of 7 over 5 close parentheses end cell row blank equals cell fraction numerator negative 5 cross times up diagonal strike 2 to the power of 7 end strike over denominator up diagonal strike 2 to the power of 7 end strike cross times open parentheses negative 5 close parentheses end fraction end cell row blank equals cell fraction numerator negative 5 over denominator negative 5 end fraction end cell row blank equals 1 end table$

Dengan demikian, nilai dari $open parentheses fraction numerator negative 5 over denominator 8 end fraction times open parentheses negative 3 close parentheses squared over 4 times 1 over 6 squared close parentheses divided by open parentheses negative 2 to the power of 7 over 5 close parentheses to the power of negative 1 end exponent$ adalah .