Pertanyaan

Tentukan hasil dari: b. ∣ ∣ − 2 5 × 3 ∣ ∣ ∣ − 24 ∣ ( − ∣ ∣ 6 1 ∣ ∣ )

Tentukan hasil dari:

b. $∣ ∣ \frac{5}{- 2} \times 3 ∣ ∣ ∣ - 24 ∣ (- ∣ ∣ \frac{1}{6} ∣ ∣)$

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H. Eka

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

Jawaban terverifikasi

Jawaban

hasil dari

hasil dari $table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar fraction numerator 5 over denominator negative 2 end fraction cross times 3 close vertical bar open vertical bar negative 24 close vertical bar open parentheses negative open vertical bar 1 over 6 close vertical bar close parentheses end cell equals cell negative 30 end cell end table$

Pembahasan

Nilai mutlak dari sebarang bilangan , yang dinotasikan dengan , didefinisikansebagai berikut. Ingat sifat nilai mutlak: Berdasarkan definisi tersebut, penyelesaian soal di atas, yaitu: Dengan demikian, hasil dari

Nilai mutlak dari sebarang bilangan x element of R , yang dinotasikan dengan open vertical bar x close vertical bar , didefinisikan sebagai berikut.

open vertical bar x close vertical bar equals open curly brackets table attributes columnalign left end attributes row cell x space text jika end text space x greater or equal than 0 end cell row cell negative x space text jika end text space x less than 0 end cell end table close

Ingat sifat nilai mutlak:

open vertical bar a times b close vertical bar equals open vertical bar a close vertical bar open vertical bar b close vertical bar

open vertical bar a divided by b close vertical bar equals open vertical bar a close vertical bar divided by open vertical bar b close vertical bar

open vertical bar negative a close vertical bar equals open vertical bar a close vertical bar

Berdasarkan definisi tersebut, penyelesaian soal di atas, yaitu:

$table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open vertical bar fraction numerator 5 over denominator negative 2 end fraction cross times 3 close vertical bar open vertical bar negative 24 close vertical bar open parentheses negative open vertical bar 1 over 6 close vertical bar close parentheses end cell row blank equals cell open vertical bar fraction numerator 5 over denominator negative 2 end fraction close vertical bar open vertical bar 3 close vertical bar open vertical bar negative 24 close vertical bar open parentheses negative fraction numerator open vertical bar 1 close vertical bar over denominator open vertical bar 6 close vertical bar end fraction close parentheses end cell row blank equals cell 5 over 2 cross times 3 cross times 24 cross times open parentheses negative 1 over 6 close parentheses end cell row blank equals cell negative 30 end cell end table$

Dengan demikian, hasil dari $table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar fraction numerator 5 over denominator negative 2 end fraction cross times 3 close vertical bar open vertical bar negative 24 close vertical bar open parentheses negative open vertical bar 1 over 6 close vertical bar close parentheses end cell equals cell negative 30 end cell end table$