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Tabel permintaan dan penawaran:   Berdasarkan tabel diatas, maka harga keseimbangan adalah....

Pertanyaan

Tabel permintaan dan penawaran:


 


Berdasarkan tabel diatas, maka harga keseimbangan adalah....undefined 

  1. (30,150)undefined 

  2. (30,175)undefined 

  3. (30,260)undefined 

  4. (150,30)undefined 

Pembahasan Soal:

Diketahui:

  • P1 = 250, P2 = 255
  • Permintaan : Q1 = 10, Q2= 20
  • Penawaran : Q1 = 35, Q2 = 40

Ditanya: Harga keseimbangan

Jawab:

  • Mencari fungsi Qd

    begin mathsize 14px style fraction numerator straight P minus straight P 1 over denominator straight P 2 minus straight P 1 end fraction equals fraction numerator straight Q minus straight Q 1 over denominator straight Q 2 minus straight Q 1 end fraction fraction numerator straight P minus 250 over denominator 255 minus 250 end fraction equals fraction numerator straight Q minus 10 over denominator 20 minus 10 end fraction fraction numerator straight P minus 250 over denominator 5 end fraction space equals space fraction numerator straight Q minus 10 over denominator 10 end fraction 5 straight Q minus 50 space equals space 10 straight P minus 2.500 5 straight Q space equals 10 straight P minus 2.500 plus 50 5 straight Q space equals 10 straight P minus 2.450 straight Q space equals space 2 straight P minus 490 end style
                   
  • Mencari fungsi Qs

    begin mathsize 14px style fraction numerator straight P minus straight P 1 over denominator straight P 2 minus straight P 1 end fraction equals fraction numerator straight Q minus straight Q 1 over denominator straight Q 2 minus straight Q 1 end fraction fraction numerator straight P minus 250 over denominator 255 minus 250 end fraction equals fraction numerator straight Q minus 40 over denominator 35 minus 40 end fraction fraction numerator straight P minus 250 over denominator 5 end fraction equals fraction numerator straight Q minus 40 over denominator negative 5 end fraction 5 straight Q minus 200 space equals space minus 5 straight P plus 1.250 5 straight Q space equals space minus 5 straight P plus 1.250 plus 200 5 straight Q space equals space minus 5 straight P plus 1.450 straight Q space equals space minus straight P plus 290 end style 
     
  • Mencari nilai P

    begin mathsize 14px style Qd equals Qs 2 straight P minus 490 equals negative straight P plus 290 2 straight P plus straight P space equals space 290 plus 490 3 straight P space equals space 780 straight P space equals space 260 end style 
     
  • Mencari  nilai Q

    begin mathsize 14px style straight Q equals 2 straight P minus 490 straight Q equals space 2 left parenthesis 260 right parenthesis minus 490 straight Q equals space 520 minus 490 straight Q equals 30 end style

Berdasarkan perhitungan diatas, harga keseimbangannya ada pada titik (30, 260)

Jadi, jawaban yang tepat adalah C.undefined 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 02 April 2021

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