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Pertanyaan

Seorang siswa mencampurkan asam lemah C H subscript 3 C O O H 0,1 M sebanyak 50 mL dengan basa kuat NaOH 0,1 M. Hitung pH larutan pada saat :

  • Sebelum penambahan NaOH 0,1 M
  • Setelah ditambah 10 mL NaOH 0,1 M
  • Setelah ditambah 25 mL NaOH 0,1 M

J. Siregar

Master Teacher

Mahasiswa/Alumni Universitas Negeri Medan

Jawaban terverifikasi

Jawaban

pH campuran sebelum dan setelah penambahan NaOH 0,1 M secara berturut-turut adalah 3, 5 - log 4, dan 5.

Pembahasan

Penentuan pH campuran sebagai berikut.

  • Sebelum penambahan NaOH 0,1 M berarti pH larutan ditentukan oleh pH asam lemah C H subscript 3 C O O H.

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of K subscript a cross times M end root end cell row blank equals cell square root of 10 to the power of negative sign 5 end exponent cross times 0 comma 1 end root end cell row blank equals cell square root of 10 to the power of negative sign 6 end exponent end root end cell row blank equals cell 10 to the power of negative sign 3 end exponent end cell row blank blank blank row pH equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row blank equals cell negative sign log space 10 to the power of negative sign 3 end exponent end cell row blank equals 3 end table 

  • Setelah ditambah 10 mL NaOH 0,1 M

table attributes columnalign right center left columnspacing 0px end attributes row cell n space C H subscript 3 C O O H end cell equals cell M cross times V end cell row blank equals cell 0 comma 1 cross times 50 end cell row blank equals cell 5 space mmol end cell row cell n space Na O H end cell equals cell M cross times V end cell row blank equals cell 0 comma 1 cross times 10 end cell row blank equals cell 1 space mmol end cell end table 

 

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell K subscript a cross times fraction numerator mol space C H subscript 3 C O O H over denominator mol space C H subscript 3 C O O Na end fraction end cell row blank equals cell 10 to the power of negative sign 5 end exponent cross times fraction numerator 4 space mmol over denominator 1 space mmol space end fraction end cell row blank equals cell 4 cross times 10 to the power of negative sign 5 end exponent end cell row pH equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row blank equals cell negative sign log space 4 cross times 10 to the power of negative sign 5 end exponent end cell row blank equals cell 5 minus sign log space 4 end cell end table 

  • Penambahan 25 mL NaOH 0,1 M mengubah setengah dari jumlah awal C H subscript 3 C O O H .

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell K subscript a cross times fraction numerator mol space C H subscript 3 C O O H over denominator mol space C H subscript 3 C O O Na end fraction end cell row blank equals cell 10 to the power of negative sign 5 end exponent cross times fraction numerator left parenthesis 5 minus sign 2 comma 5 right parenthesis space mmol over denominator 2 comma 5 space mmol space end fraction end cell row blank equals cell 10 to the power of negative sign 5 end exponent end cell row pH equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row blank equals cell 10 to the power of negative sign 5 end exponent end cell row blank equals 5 end table 

Jadi, pH campuran sebelum dan setelah penambahan NaOH 0,1 M secara berturut-turut adalah 3, 5 - log 4, dan 5.

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