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Sebanyak 60 mL larutan amonia tepat bereaksi dengan 40 mL H 2 ​ SO 4 ​ 0,15 M. Jika diketahui K b ​ NH 3 ​ = 1 × 1 0 − 5 , tentukanpH larutan amonia semula!

Sebanyak 60 mL larutan amonia tepat bereaksi dengan 40 mL  0,15 M. Jika diketahui , tentukan pH larutan amonia semula!

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pH amonia adalah .

pH amonia adalah begin mathsize 14px style 11 plus log space square root of 2 end style.undefined

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Suatu larutan dikatakan tepat bereaksi jika memiliki jumlah mol yang sama. Amonia merupakan basa lemah, sehingga pH nya dapat dihitung dengan persamaan berikut. Jadi, pH amonia adalah .

Suatu larutan dikatakan tepat bereaksi jika memiliki jumlah mol yang sama.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript H subscript 2 S O subscript 4 end subscript cross times V subscript H subscript 2 S O subscript 4 end subscript cross times a end cell equals cell M subscript N H subscript 3 end subscript cross times V subscript N H subscript 3 end subscript cross times b end cell row cell 0 comma 15 space M cross times 40 space mL cross times 2 end cell equals cell M subscript N H subscript 3 end subscript cross times 60 space mL cross times 1 end cell row cell M subscript N H subscript 3 end subscript end cell equals cell fraction numerator 0 comma 15 space M cross times 40 space mL cross times 2 over denominator 60 space mL cross times 1 end fraction end cell row cell M subscript N H subscript 3 end subscript end cell equals cell 0 comma 2 space M end cell end table end style    

Amonia merupakan basa lemah, sehingga pH nya dapat dihitung dengan persamaan berikut.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of K subscript b cross times M subscript N H subscript 3 end subscript end root end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of 1 cross times 10 to the power of negative sign 5 end exponent cross times 2 cross times 10 to the power of negative sign 1 end exponent end root end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of 2 cross times 10 to the power of negative sign 6 end exponent end root end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of 2 cross times 10 to the power of negative sign 3 end exponent end cell row blank blank blank row pOH equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row pOH equals cell negative sign log space left parenthesis square root of 2 cross times 10 to the power of negative sign 3 end exponent right parenthesis end cell row pOH equals cell 3 minus sign log space square root of 2 end cell row blank blank blank row pH equals cell 14 minus sign pOH end cell row pH equals cell 14 minus sign left parenthesis 3 minus sign log space square root of 2 right parenthesis end cell row pH equals cell 11 plus log space square root of 2 end cell end table end style   

Jadi, pH amonia adalah begin mathsize 14px style 11 plus log space square root of 2 end style.undefined

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