Pertanyaan

Sebanyak 50 mL larutan K 2 ​ CrO 4 ​ 1 0 − 2 M masing masing dimasukkan ke dalam lima wadah yang berisi ion Ba 2 + , Ca 2 + , Cu 2 + , Sr 2 + dan Pb 2 + dengan volume dan konsentrasi yang sama. Jika Ksp: BaCrO 4 ​ = 1 , 2 × 1 0 − 10 CaCrO 4 ​ = 7 , 1 × 1 0 − 14 SrCrO 4 ​ = 4 × 1 0 − 5 CuCrO 4 = 3 , 6 × 1 0 − 6 PbCrO 4 ​ = 2 , 8 × 1 0 − 13 Senyawa yang mengendap adalah…

Sebanyak 50 mL larutan   M masing masing dimasukkan ke dalam lima wadah yang berisi ion , , ,  dan  dengan volume dan konsentrasi yang sama. Jika Ksp:
 

  =    

 =    

 =    

  =    

  =     


Senyawa yang mengendap adalah…

  1. undefined dan undefined 

  2. undefined dan undefined

  3. undefined dan begin mathsize 14px style Cu Cr O 4 end style 

  4. undefined dan undefined

  5. undefined dan undefined 

Q. 'Ainillana

Master Teacher

Mahasiswa/Alumni Universitas Negeri Yogyakarta

Jawaban terverifikasi

Jawaban

senyawa yang mengendap adalah dan . Tidak ada pilihan opsi yang sesuai.

senyawa yang mengendap adalah begin mathsize 14px style Ba Cr O subscript bold 4 bold comma bold space Ca Cr O subscript bold 4 bold comma bold space Cu Cr O subscript bold 4 bold comma bold space end subscript end style dan begin mathsize 14px style Pb Cr O subscript bold 4 end style. Tidak ada pilihan opsi yang sesuai.

Pembahasan

Untuk mengetahui senyawa yang mengendap, maka dibandingkan nilai dengan masing-masing. Mol Maka setelah dicampur dengan ion-ion dengan konsentrasi dan volume sama, Konsentrasi ion-ion: Jadi, senyawa yang mengendap adalah dan . Tidak ada pilihan opsi yang sesuai.

Untuk mengetahui senyawa yang mengendap, maka dibandingkan nilai begin mathsize 14px style Q subscript sp end style dengan undefined masing-masing.

Mol begin mathsize 14px style K subscript 2 Cr O subscript 4 double bond M cross times V equals 0 comma 01 cross times 50 equals 0 comma 5 space mmol end style  

begin mathsize 14px style K subscript 2 Cr O subscript 4 equilibrium 2 K to the power of plus sign and Cr O subscript 4 to the power of 2 minus sign end exponent 0 comma 5 space mmol space space 1 space mmol space space 0 comma 5 space mmol end style 

Maka setelah dicampur dengan ion-ion dengan konsentrasi dan volume sama,

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell left square bracket Cr O subscript 4 to the power of 2 minus sign end exponent right square bracket end cell equals cell mol over V subscript camp end cell row blank equals cell fraction numerator 0 comma 5 space mmol over denominator 100 space mL end fraction end cell row blank equals cell 5 cross times 10 to the power of negative sign 3 end exponent space end cell end table end style 

Konsentrasi ion-ion:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets Ba to the power of 2 plus sign close square brackets end cell equals cell mol over V subscript campuran end cell row blank equals cell fraction numerator M cross times V over denominator V subscript camp end fraction end cell row blank equals cell fraction numerator 10 to the power of negative sign 2 end exponent cross times 50 over denominator 100 end fraction end cell row blank equals cell 5 cross times 10 to the power of negative sign 3 end exponent space end cell end table end style  

begin mathsize 14px style open square brackets Ba to the power of 2 plus sign close square brackets double bond open square brackets Ca to the power of 2 plus sign close square brackets double bond open square brackets Cu to the power of 2 plus sign close square brackets double bond open square brackets Sr to the power of 2 plus sign close square brackets double bond open square brackets Pb to the power of 2 plus sign close square brackets equals 5 cross times 10 to the power of negative sign 3 end exponent end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell Q subscript sp space Ba Cr O subscript 4 end cell equals cell open square brackets Ba to the power of 2 plus sign close square brackets left square bracket Cr O subscript 4 to the power of 2 minus sign end exponent right square bracket end cell row blank equals cell left parenthesis 5 cross times 10 to the power of negative sign 3 end exponent right parenthesis left parenthesis 5 cross times 10 to the power of negative sign 3 end exponent right parenthesis end cell row blank equals cell 25 cross times 10 to the power of negative sign 6 end exponent end cell row blank equals cell 2 comma 5 cross times 10 to the power of negative sign 5 end exponent space end cell row cell K subscript sp space Ba Cr O subscript 4 end cell equals cell 1.2 cross times 10 to the power of negative sign 10 end exponent end cell row cell Q subscript sp space end subscript end cell greater than cell K subscript sp space open parentheses mengendap close parentheses end cell end table end style    

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell Q subscript sp space Ca Cr O subscript 4 end cell equals cell open square brackets Ca to the power of 2 plus sign close square brackets left square bracket Cr O subscript 4 to the power of 2 minus sign end exponent right square bracket end cell row blank equals cell left parenthesis 5 cross times 10 to the power of negative sign 3 end exponent right parenthesis left parenthesis 5 cross times 10 to the power of negative sign 3 end exponent right parenthesis end cell row blank equals cell 25 cross times 10 to the power of negative sign 6 end exponent end cell row blank equals cell 2 comma 5 cross times 10 to the power of negative sign 5 end exponent space end cell row cell K subscript sp Ca Cr O subscript 4 end cell equals cell 7 comma 1 cross times 10 to the power of negative sign 14 end exponent end cell row cell Q subscript sp space end subscript end cell greater than cell K subscript sp space open parentheses mengendap close parentheses end cell end table end style   

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell Q subscript sp space Cu Cr O subscript 4 end cell equals cell open square brackets Cu to the power of 2 plus sign close square brackets left square bracket Cr O subscript 4 to the power of 2 minus sign end exponent right square bracket end cell row blank equals cell left parenthesis 5 cross times 10 to the power of negative sign 3 end exponent right parenthesis left parenthesis 5 cross times 10 to the power of negative sign 3 end exponent right parenthesis end cell row blank equals cell 25 cross times 10 to the power of negative sign 6 end exponent end cell row blank equals cell 2 comma 5 cross times 10 to the power of negative sign 5 end exponent space end cell row cell K subscript sp space Cu Cr O subscript 4 end cell equals cell 3 comma 6 cross times 10 to the power of negative sign 6 end exponent end cell row cell Q subscript sp space end subscript end cell greater than cell K subscript sp space open parentheses mengendap close parentheses end cell end table end style  

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell Q subscript sp space Sr Cr O subscript 4 end cell equals cell open square brackets Sr to the power of 2 plus sign close square brackets left square bracket Cr O subscript 4 to the power of 2 minus sign end exponent right square bracket end cell row blank equals cell left parenthesis 5 cross times 10 to the power of negative sign 3 end exponent right parenthesis left parenthesis 5 cross times 10 to the power of negative sign 3 end exponent right parenthesis end cell row blank equals cell 25 cross times 10 to the power of negative sign 6 end exponent end cell row blank equals cell 2 comma 5 cross times 10 to the power of negative sign 5 end exponent space end cell row cell K subscript sp space Sr Cr O subscript 4 end cell equals cell 4 cross times 10 to the power of negative sign 5 end exponent end cell row cell Q subscript sp space end subscript end cell less than cell K subscript sp space left parenthesis belum space mengendap right parenthesis end cell end table end style  

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell Q subscript sp space Pb Cr O subscript 4 end cell equals cell open square brackets Pb to the power of 2 plus sign close square brackets left square bracket Cr O subscript 4 to the power of 2 minus sign end exponent right square bracket end cell row blank equals cell left parenthesis 5 cross times 10 to the power of negative sign 3 end exponent right parenthesis left parenthesis 5 cross times 10 to the power of negative sign 3 end exponent right parenthesis end cell row blank equals cell 25 cross times 10 to the power of negative sign 6 end exponent end cell row blank equals cell 2 comma 5 cross times 10 to the power of negative sign 5 end exponent end cell row cell K subscript sp space end subscript Pb Cr O subscript 4 end cell equals cell 2 comma 8 cross times 10 to the power of negative sign 13 end exponent end cell row cell space Q subscript sp space end subscript end cell greater than cell K subscript sp space open parentheses mengendap close parentheses end cell end table end style   

Jadi, senyawa yang mengendap adalah begin mathsize 14px style Ba Cr O subscript bold 4 bold comma bold space Ca Cr O subscript bold 4 bold comma bold space Cu Cr O subscript bold 4 bold comma bold space end subscript end style dan begin mathsize 14px style Pb Cr O subscript bold 4 end style. Tidak ada pilihan opsi yang sesuai.

1rb+

SULTHAN SYAHRUL BUNAYYA ANHUTIKNO

Jawaban tidak sesuai

ABET NEGO SEMBIRING

Jawaban tidak sesuai Pembahasan tidak legkap

Iklan

Pertanyaan serupa

Kelarutan Mg ( OH ) 2 ​ (Mr = 58) dalam 100 mL larutan jenuhnya sebanyak 0,58 mg maka pH larutan jenuh adalah . . . .

289

0.0

Jawaban terverifikasi

Iklan

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Fitur Roboguru

Topik Roboguru

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia