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Sebanyak 4 gram serbuk kalsium hidroksida dilarutkan dalam air hingga 100 ml. Hitung volume larutan asam klorida 0,2 M yang diperlukan untuk menetralkan 25 ml larutan kalsium hidroksida tersebut. (italic A subscript r O = 16 dan Ca = 40)

A. Chandra

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

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Jawaban

volume HCl yang diperlukan adalah 135 ml.

Pembahasan

Menentukan molaritas Ca open parentheses O H close parentheses subscript 2:

table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r space Ca open parentheses O H close parentheses subscript 2 end cell equals cell left parenthesis 1 cross times italic A subscript r space Ca right parenthesis plus left parenthesis 2 cross times italic A subscript r space O right parenthesis plus left parenthesis 2 cross times italic A subscript r space H right parenthesis end cell row blank equals cell left parenthesis 1 cross times 40 right parenthesis plus left parenthesis 2 cross times 16 right parenthesis plus left parenthesis 2 cross times 1 right parenthesis end cell row blank equals cell 40 plus 32 plus 2 end cell row blank equals cell 74 space g space mol to the power of negative sign 1 end exponent end cell end table 

table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript Ca open parentheses O H close parentheses subscript 2 end subscript end cell equals cell m over italic M subscript r end cell row blank equals cell 4 over 74 end cell row blank equals cell 0 comma 054 space mol end cell end table 

table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript Ca open parentheses O H close parentheses subscript 2 end subscript end cell equals cell n over V end cell row blank equals cell fraction numerator 0 comma 054 over denominator 0 comma 1 end fraction end cell row blank equals cell 0 comma 54 space M end cell end table 

Menentukan volume HCl:

table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript Ca open parentheses O H close parentheses subscript 2 end subscript cross times V subscript Ca open parentheses O H close parentheses subscript 2 end subscript cross times valensi end cell equals cell M subscript HCl cross times V subscript HCl cross times valensi end cell row cell 0 comma 54 cross times 25 cross times 2 end cell equals cell 0 comma 2 cross times V subscript HCl cross times 1 end cell row cell V subscript HCl end cell equals cell fraction numerator 27 over denominator 0 comma 2 end fraction end cell row blank equals cell 135 space ml end cell end table 

Jadi, volume HCl yang diperlukan adalah 135 ml.

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