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Pertanyaan

Sebanyak 2,62 gram  hidrat dari kalsium sulfat dipanaskan sampai semua air kristalnya menguap sesuai persamaan reaksi: CaSO4 . x H2O (s) -> CaSO4 (s) + x H2O (g). Jika massa padatan kalsium sulfat yang terbentuk adalah 1,36 gram, rumus senyawa hidrat tersebut adalah.. (Ar Ca = 40; S = 32; O = 16)

  1. CaSO4 . 3 H2O

  2. CaSO4 . 4 H2O

  3. CaSO4 . 5 H2O

  4. CaSO4 . 6 H2O

  5. CaSO4 . 7 H2O

M. Robo

Master Teacher

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Pembahasan

M a s s a space h i d r a t space left parenthesis C a S O subscript 4. x H subscript 2 O right parenthesis space a d a l a h space 2 comma 62 space g r a m comma space k e t i k a space d i p a n a s k a n space a d a space m a s s a space h i l a n g comma space m a s s a space y a n g space h i l a n g space i n i space m e r u p a k a n space m a s s a space H subscript 2 O. space K e m u d i a n space m a s s a space t e r s i s a space a d a l a h space 1 comma 36 space g r a m space i n i space m e r u p a k a n space m a s s a space a n h i d r a t space left parenthesis g a r a m space m u r n i right parenthesis. space  M a s s a space H subscript 2 O space equals space m a s s a space h i d r a t space minus space m a s s a space a n h i d r a t  space space space space space space space space space space space space space space space space space space space space space space equals space 2 comma 62 space g r a m space minus space 1 comma 36 space g r a m  space space space space space space space space space space space space space space space space space space space space space space equals space 1 comma 26 space g r a m  K e m u d i a n comma space u n t u k space m e n e n t u k a n space j u m l a h space H subscript 2 O space m a k a space h i t u n g space p e r b a n d i n g a n space m o l space d a r i space H subscript 2 O space d a n space g a r a m.  m o l space C a S O subscript 4 space colon space m o l space H subscript 2 O space equals space fraction numerator m a s s a space C a S O subscript 4 over denominator M r space C a S O subscript 4 end fraction space colon space fraction numerator m a s s a space H subscript 2 O over denominator M r space H subscript 2 O end fraction  space space space space equals space fraction numerator 1 comma 36 space g over denominator 136 end fraction space colon space fraction numerator 1 comma 26 space g over denominator 18 end fraction  space space space space equals 0 comma 01 space colon space 0 comma 07  space space space space equals space 1 space colon space 7    S e h i n g g a space X thin space a d a l a h space 7  M a k a space r u m u s space h i d r a t n y a space equals space C a S O subscript 4.7 H subscript 2 O

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Sebanyak 249,5 gram kristal CuSO4​.xH2​O dipanaskan sehingga menghasilkan 159,5 gram CuSO4​, menurut reaksi: CuSO4​.xH2​O(s)→CuSO4​(s)+xH2​O(g) Rumus senyawa kristal tersebut adalah... (Ar Cu = 63,5...

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